The equation of line s is y=1/3x-3. The equation of line t is y=-x+5. the equations of line s and t form a system of equations.
The solution to the system of equations is located at point P. What would the graph look like?
1 answer:
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Answer:
Step-by-step explanation:
For the given piecewise function,
Let the equation of the segment AB is,
y = ax + 7 where x < -2
Since a point (-2, 3) lies on the given line,
3 = a(-2) + 7
3 - 7 = -2a
a = 2
Therefore, f(x) = 2x + 7 when x < -2
For the segment BC,
f(x) = 3 where -2 ≤ x ≤ 2
For the segment CD,
f(x) = bx + 9
Since a point (2, 3) lies on this segment,
f(2) = 2b + 9 = 3
2b = 3 - 9
b = -3
Therefore, equation of segment CD will be,
f(x) = (-3)x + 9 where x > 2
