M2 would be (3x-54) just like m5
To solve, we will follow the steps below:
3x+y=11 --------------------------(1)
5x-y=21 ------------------------------(2)
since y have the same coefficient, we can eliminate it directly by adding equation (1) and (2)
adding equation (1) and (2) will result;
8x =32
divide both-side of the equation by 8
x = 4
We move on to eliminate x and then solve for y
To eliminate x, we have to make sure the coefficient of the two equations are the same.
We can achieve this by multiplying through equation (1) by 5 and equation (2) by 3
The result will be;
15x + 5y = 55 ----------------------------(3)
15x - 3y =63 --------------------------------(4)
subtract equation (4) from equation(3)
8y = -8
divide both-side of the equation by 8
y = -1
Yo sup??
cosx>0 in the 1st and 4th quadrant.
tanx>0 in the 1st and 3rd quadrant.
therefore the common solution is x lies in 1st quadrant.
Hence the correct answer is option A.
Hope this helps
You have to get r by itself on one side. Multiply both sides by 238 to cancel it out of the denominator on the left side.
You are left with r = 8 × 238 or r = 1904.
To check, plug 1904 back into the equation.
1904 ÷ 238 = 8
8 = 8 (True)
Answer: 720
Step-by-step explanation:
5%=36
1%=36/5
1%=7.2
100%=7.2*100
100%=720 students
