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AysviL [449]
3 years ago
12

Select ALL the ratios that are equivalent to 8:6.

Mathematics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:a

4:3

Step-by-step explanation: i hop this help

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Given f(x) and g(x) = f(x) + k, use the graph to determine the value of k.
zalisa [80]
<h3>Answer: C) 4</h3>

All points on the blue curve f(x) are shifted up 4 units to get corresponding points on the red curve g(x). For example, the point (0,-3) moves up 4 units to (0,1).

g(x) = f(x)+k

g(x) = f(x)+4

3 0
4 years ago
X = 42 whats the answer
hjlf

Answer:

x is 42

X = 42

Step-by-step explanation:

3 0
3 years ago
The equation of a line L1 is y=5x+1
Korolek [52]

Answer:

Lines are considered parallel if their slopes are the same.  In Line 1, the slope is 5 and in Line 2, when we solve for 'y', we also get a slope of 5, which means the two lines are parallel.  

Step-by-step explanation:

In order to find slope, it is easiest to put the equation in slope-intercept form, or y=mx + b, where m = slope and b=y-intercept.  In L1, y=5x +1 indicates a slope of 5.  In L2, the equation is not in slope-intercept form, so we must solve for 'y' using inverse operations:  2y - 10x +3 = 0, start by subtracting 3 from both sides of the equal sign:  2y - 10x +3 -3 = 0 - 3 gives us 2y - 10x = -3.  Then add '10x' to both sides:  2y - 10x + 10x = -3 + 10x gives us 2y = 10x - 3.  Lastly, divide all terms by 2:  2y/2 = (10/2)x - 3/2 or y = 5x - 1.5.  Now that L2 is in slope-intercept form, we can see that m=5 as in L1, so since they have the same slope, they are parallel lines.  

8 0
3 years ago
Read 2 more answers
In tennis, a first serve can be an ace, a fault, or it can be returned. In one match, a tennis player hit 24 aces, which was 25
Anastaziya [24]

Answer:

16 faults

Step-by-step explanation:

<u><em>The correct question is</em></u>

In tennis, a first serve can be an ace, a fault, or it can be returned. In one match, a tennis player hit 24 aces, which was 2/5 of all her first serves. If 1/3 of her first serves were returned, how many of the tennis player's first serves were faults?

Let

x -----> the number of all her first servers

y ----> the number of first services returned

z ---> the number of first services faults

we know that

The number of aces plus the number of returned plus the number of faults must be equal to the number of all her first services

so

x=24+y+z

step 1

Find out the number of all her first servers

we have that

24=\frac{2}{5}x

Solve for x

x=24(5)/2\\x=60\ first\ services

step 2

Find out the number of first services returned

y=\frac{1}{3}x

substitute the value of x

y=\frac{1}{3}(60)=20\ returned

step 3

Find out the number of first services faults

x=24+y+z

we have

x=60\\y=20

substitute and solve for z

60=24+20+z

60=44+z

z=16\ faults

6 0
3 years ago
How many solutions does 3r-4=11-2r have
horsena [70]

Answer:

it only has one solution and it is r = 3

Step-by-step explanation:

4 0
3 years ago
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