Question

Suppose a culture of bacteria begins with 5000 cells and dies by 30% each year. Write an equation that represents this situation.

Answer 1

Answer:

$A(t)=5000(0.7)^t$

Step-by-step explanation:

The problem presented is one in which the population of the bacteria  depreciates by a decay factor r every year.

Since it is a decay problem, we use the model:

$A(t)=P(1-r)^t$

Initial Population, P=5000

Decay Rate,r=30%=0.3

t=time interval

Therefore, the equation that represents this situation is:

$A(t)=5000(1-0.3)^t$

$A(t)=5000(0.7)^t$