Answer:
The maximum distance to the nearest kilometer between Westford and Centerville is 111.43 km.
Step-by-step explanation:
Local train stats:
Rate = 60 km/h
Distance = x km
Time = x/60 hours
Express train stats:
Rate = 80 km/h
Distance = 
km
Time = 
hours
Now we will equate both the times.
x = 83.57 km
km
Hence, the maximum distance to the nearest kilometer between Westford and Centerville is 111.43 km.
Use the slope formula and slope-intercept form
y=mx+b
to find the equation.
y=2/11x + 4/11
Hope this helps
Answer:
∠y = 62.5°
∠x = 27.5°
Step-by-step explanation:
z is right angle. ∠z = 90°
∠x = ∠y - 35
∠x + ∠y + ∠z = 180 {Angle sum property of triangle}
y - 35 + y + 90 = 180
y + y - 35 + 90 = 180 {Combine like terms}
2y + 55 = 180
2y = 180 -55 {Subtract 55 from both sides}
2y = 125 {Divide both sides by 2}
y = 125 /2
∠y = 62.5°
∠x = 62.5 - 35 = 27.5°
A bearing of 34° corresponds to corresponding angle of θ=90-34=56°
The (x,y) values for the position of the ship after completing its first heading are:
x=(10.4cos 56)
y=(10.4sin56)
The trigonometric angle for θ=90-90=0
The (x,y) values for the postion of the ship after completing the second bearing is:
x=(10.4 cos56)+(4.6cos0)≈10.4 mi
y=(10.4sin56)+(4.6sin0)≈8.6mi
the distance from the port will therefore be:
d=√(10.4²+8.6²)≈13.5 miles
It trigonometric angles is:
θ=arctan(y/x)
θ=arctan(8.6/10.4)
θ≈39.6°
Thus the bearing angle is:
90-39.6=50.4°
Answer
Just runs 7 minutes per mile
Step by Step explanation
Divide 11 by both numbers which leaves you with
1/6
Because you have to divide 11 by 11 and 67 by 11
when you calculate it you get 6.090909091
so you can round it to 7.
