Answer:
x₁ = 0.1878 m
Explanation:
For this exercise we will use conservation of energy
starting point. Highest point
Em₀ = U = m g h
final point. Lowest point with fully compressed spring
Em_f = K_e + U
Em_f = ½ K x² + m g x
energy is conserved
Em₀ = Em_f
m g h = ½ K x² + m g x
½ K x² + mg (x- h) = 0
let's substitute
½ 7.3 x² + 0.030 9.8 (x- 0.25) = 0
3.65 x² + 0.294 (x- 0.25) = 0
x² + 0.080548 (x- 0.25) = 0
x² - 0.020137 + 0.080548 x = 0
x² + 0.080548 x - 0.020137 = 0
let's solve the quadratic equation
x = [0.080548 ±√ (0.080548² + 4 0.020137)] / 2
x = [0.080548 ± 0.29502] / 2
x₁ = 0.1878 m
x₂ = -0.1072 m
These are the compression and extension displacement of the spring
Answer:
<u>The asteroid was not detected until it was extremely close to Earth. </u>
Explanation:
According to data from NASA, the Asteroid named 'Astriod 2019 OK', was detected when it was extremely close to earth with just about an estimated distance of 73,000 kilometers (45,000 miles) from the Earth.
Scientists were concerned at the proximity of this space object to the Earth before it was discovered, and it brought about a cause of concern that since it was not extremely large (estimated 57 to 130 meters wide) it creates a potential for other smaller asteroids to escape detection and struck the earth.
Answer: <u><em>C. Steel</em></u>
Explanation: <em><u>When a sound wave travels through a solid body consisting</u></em>
<em><u /></em>
<em><u>of an elastic material, the velocity of the wave is relatively</u></em>
<em><u /></em>
<em><u>high. For instance, the velocity of a sound wave traveling</u></em>
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<em><u>through steel (which is almost perfectly elastic) is about</u></em>
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<em><u>5,060 meters per second. On the other hand, the velocity</u></em>
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<em><u>of a sound wave traveling through an inelastic solid is</u></em>
<em><u /></em>
<em><u>relatively low. So, for example, the velocity of a sound wave</u></em>
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<em><u>traveling through lead (which is inelastic) is approximately</u></em>
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<em><u>1,402 meters per second.</u></em>
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<u><em /></u>
Ohms law is V = IR
from this we can rearrange so that I or current is the subject
I = V/R
so if both V and R are doubled, we can represent it as such
I = 2V/2R
The 2s will cancel out hence they effect on the current is nil