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Ivenika [448]
3 years ago
9

Before you conduct your experiment, you need to form a hypothesis. A hypothesis is a prediction of what you think will happen in

the experiment. The hypothesis is a statement that describes “if” a certain set of circumstances are present “then” there will be a specific result that will occur. Hint on how to write a hypothesis: If____________________then_______________.
Physics
1 answer:
Stolb23 [73]3 years ago
5 0

Example: A apple rotting.

If I put my apple in a fridge, then it would not rot as fast because it is in a cooled area. (example)

Hope it helps! Brainiest Answer would be amazing!

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A disk-shaped merry-go-round of radius 2.13 m and mass 175 kg rotates freely with an angular speed of 0.651 rev/s. A 55.4 kg per
GREYUIT [131]

Answer:

Explanation:

To find out the angular velocity of merry-go-round after person jumps on it , we shall apply law of conservation of ANGULAR momentum

I₁ ω₁ + I₂ ω₂ = ( I₁  + I₂ ) ω

I₁ is moment of inertia of disk , I₂ moment of inertia of running person , I is the moment of inertia of disk -man system , ω₁ and ω₂ are angular velocity of disc and man .

I₁ = 1/2 mr²

= .5 x 175 x 2.13²

= 396.97 kgm²

I₂ = m r²

= 55.4 x 2.13²

= 251.34 mgm²

ω₁ = .651 rev /s

= .651 x 2π rad /s

ω₂ = tangential velocity of man / radius of disc

= 3.51 / 2.13

= 1.65 rad/s

I₁ ω₁ + I₂ ω₂ = ( I₁  + I₂ ) ω

396.97 x  .651 x 2π + 251.34 x 1.65 = ( 396.97 + 251.34 ) ω

ω = 3.14 rad /s

kinetic energy = 1/2 I ω²

= 3196 J

8 0
3 years ago
intial velocity is 45km/h, final velocity is 0, time taken is 3 seconds,calculate the retradation of the vehicle and distance tr
V125BC [204]

Answer:

v= u+at

0=45×1000×60×60+3a

_3a=16200045

a=5400015m per sec

4 0
3 years ago
Read 2 more answers
The magnetic field at the center of a 1.0-cm-diameter loop is 2.5 mT.
olga nikolaevna [1]

Answer:

(a) The current in the wire is 19.89 A

(b) The distance from the wire is 0.159 cm

Explanation:

Given;

magnetic field, B = 2.5 mT

diameter of the wire, d = 1 cm

radius of the wire, r = 0.5 cm = 0.005 m

(a) The current in the wire is calculated as;

I = \frac{2Br}{\mu_0} \\\\I = \frac{2\times 2.5 \times 10^{-3} \times 0.005 }{4\pi \times 10^{-7} } \\\\I = 19.89 \ A

(b) The distance from the wire where the magnetic field is 2.5 mT is calculated as;

B = \frac{\mu_0 I}{2\pi d} \\\\where;\\\\d \ is \ the \ distance \ from \ the \  wire\\\\d = \frac{\mu_0 I}{2\pi B} = \frac{4 \pi \times 10^{-7} \times 19.89}{2\pi \times 2.5 \times 10^{-3}}  = 0.00159 \ m = 0.159 \ cm

6 0
3 years ago
A ball is kicked from the top of a building with a velocity of 50 m/s and lands 165 m away from the base of the building.
Nadusha1986 [10]

The height of the building is 53.4 m (projectile motion)

Explanation:

The motion of the ball is a projectile motion, so it follows a parabolic path which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction  

First of all, we consider the horizontal motion, which is a uniform motion at constant speed. The equation that gives the horizontal distance travelled is:

d=v_x t  

where:

v_x = 50 m/s is the horizontal velocity of the ball, which is constant since there are no forces in this direction

d = 165 m is the horizontal distance travelled by the ball

Solving for t, we find the time of flight:

t=\frac{d}{v_x}=\frac{165}{50}=3.3 s

Now we analyze the vertical motion: it is an accelerated motion, we can use the suvat equation

s=ut+\frac{1}{2}at^2  

where  

s is the vertical displacement, which is the height of the building

u = 0 is the initial vertical velocity of the ball

t = 3.3 s is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity  

Solving for s, we find the height of the building:

s=0+\frac{1}{2}(9.8)(3.3)^2=53.4 m

Learn more about projectile motion here:

brainly.com/question/8751410

#LearnwithBrainly

6 0
3 years ago
A series R-L-C circuit is connected to a 70.0 Hz ac source that has Vrms = 80.0 V . The circuit has a resistance of 80.0 Ω and a
Andreyy89

Answer:

62.7 VA

Explanation:

The apparent power (power supplied by the source) of an AC circuit is determined by

S = \frac{(Vrms)^2}{Z}

The impedance(Z) depends on the frequency, but in this case it is given to us that it is 102 ohms at this frequency.

So:

S = \frac{(80 V)^2}{102 \Omega} = 62.7 VA

3 0
3 years ago
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