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Anuta_ua [19.1K]
3 years ago
9

I will reward brainliest!!! Please Help

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
6 0
SAS, because of the congruence

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7+4u=70-3u<br> What is U
ruslelena [56]
7+4u=70-3u \\ 7+4u+3u=70-3u+3u \\ 7+7u=70 \\ 7-7+7u=70-7 \\ 7u=63 \\ 7u/7=63/7 \\ u=9
u=9 is your answer.
Hope this helps!
5 0
3 years ago
Read 2 more answers
A coach is assessing the correlation between the number of hours spent practicing and the average number of points scored in a g
cricket20 [7]

Answer:

a) r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

b) m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

c) For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

Step-by-step explanation:

We have the following data:

Number of hours spent practicing (x) 0 0.5 1 1.5 2 2.5 3 3.5 4

Score in the game (y) 5 8 11 14 17 20 23 26 29

Part a

The correlation coefficient is given:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=9 \sum x = 18, \sum y = 153, \sum xy = 396, \sum x^2 =51, \sum y^2 =3141  

r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=51-\frac{18^2}{9}=15  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=396-\frac{18*153}{9}=90  

And the slope would be:  

m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

Part c

For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

5 0
3 years ago
Which segment shows the highest increase in the rate of change?​
n200080 [17]

Answer: Between E and G

Step-by-step explanation:

6 0
3 years ago
How to solve the system of equations algebraically over a set of real numbers
navik [9.2K]
<span>Solve the following equation in the real number system. Please show all of your work.
example: 
x³-6x²-10x+12=0
...
f(x)=x³-6x²-10x+12
A graphing calculator will show that there is one zero at x=-2
Divide f(x) by (x+2) by long division or synthetic division
(x³-6x²-10x+12)/(x+2)=x^2-8x+6

solve for other two zeros
x^2-8x+6=0
complete the square
(x^2-8x+16)+6-16=0
(x-4)^2=10
x-4=±√10
x=4±√10=7.16 and -.84
ans:
x=-2, -.84 and 7.16</span>
3 0
4 years ago
What are easy ways to study for the EOG and NCFE?
vesna_86 [32]
I am an organized person, so i make a checklist of all my notes and study them in order and that helps me a lot for the EOGs

4 0
4 years ago
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