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dimulka [17.4K]
3 years ago
7

What describes the time it takes a packet to move from one designated on the network to

Computers and Technology
1 answer:
lana66690 [7]3 years ago
5 0

Answer:Latency

Explanation:Latency is the measurement that describes about the (RTT)round trip time of a packet. RTT consist of the function of the packet travelling from the source to destination and then back again to the source port. If there is any kind of disturbance in the path of transmission then it causes the loss in the data packet.Therefore, the correct option is latency.

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A file is to be shared among different processes, each of which has a unique number. The file can beaccessed simultaneously by s
Finger [1]

Answer:

int sumid=0;    /* Shared var that contains the sum of the process ids currently accessing the file */

int waiting=0;   /* Number of process waiting on the semaphore OkToAccess */

semaphore mutex=1;   /* Our good old Semaphore variable ;) */

semaphore OKToAccess=0;    /* The synchronization semaphore */

get_access(int id)

{

    sem_wait(mutex);

    while(sumid+id > n) {

        waiting++;

        sem_signal(mutex);

        sem_wait(OKToAccess);

        sem_wait(mutex);

    }

    sumid += id;

    sem_signal(mutex);

}

release_access(int id)

{

    int i;

    sem_wait(mutex);

    sumid -= id;

    for (i=0; i < waiting;++i) {

        sem_signal(OKToAccess);

    }

    waiting = 0;

    sem_signal(mutex);

}

main()

{

    get_access(id);

    do_stuff();

    release_access(id);

}

Some points to note about the solution:

release_access wakes up all waiting processes. It is NOT ok to wake up the first waiting process in this problem --- that process may have too large a value of id. Also, more than one process may be eligible to go in (if those processes have small ids) when one process releases access.

woken up processes try to see if they can get in. If not, they go back to sleep.

waiting is set to 0 in release_access after the for loop. That avoids unnecessary signals from subsequent release_accesses. Those signals would not make the solution wrong, just less efficient as processes will be woken up unnecessarily.

5 0
3 years ago
you are using linux and need to perform a reverse lookup of the ip address 10.0.0.3. which command would you use to accomplish t
ollegr [7]

A command you would use to perform a reverse lookup of the IP address 10.0.0.3 on a Linux system: dig -x 10.0.0.3.

<h3>What is a Linux command?</h3>

A Linux command can be defined as a software program that is designed and developed to run on the command line, in order to enable an administrator (end user) of a Linux network perform both basic and advanced tasks by only entering a line of text.

<h3>What is IP address?</h3>

IP address is an abbreviation for Internet protocol address and it can be defined as a unique set of numbers that are assigned to a computer, website or other network devices, in order to successfully differentiate them from one another in an active network system.

In Computer Networking, a command which an administrator (end user) would use to perform a reverse lookup of the IP address 10.0.0.3 on a Linux system is dig -x 10.0.0.3.

Read more on Linux commands here: brainly.com/question/25480553

#SPJ1

3 0
2 years ago
T-1 is the simplest WAN data service provided by telecom carriers. It has a data rate of
-Dominant- [34]
1.544Mb/s  (megabits per second)
6 0
3 years ago
Assume that the classes listed in the Java Quick Reference have been imported where appropriate.
Neko [114]

The following java code will be written for the prescribed

<u>Explanation:</u>

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

      for(int i=0;i<arr.length;i++){

          if(name.equals(arr[i]))

              return true;

      }

      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

              this.possibleNames.remove(index);

              names = new String[this.possibleNames.size()];

              names = this.possibleNames.toArray(names);

          }

      }

  }

  public boolean isValidName(String str){

      if(str.length()==0) return false;

      for(int i=0;i<str.length();i++){

          if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

              return false;

      }

      return true;

  }

  public static void main(String[] args) {

      UserName person1 = new UserName("john","smith");

      System.out.println(person1.possibleNames);

      String[] used = {"harta","hartm","harty"};

      UserName person2 = new UserName("mary","hart");

      System.out.println("possibleNames before removing: "+person2.possibleNames);

      person2.setAvailableUserNames(used);

      System.out.println("possibleNames after removing: "+person2.possibleNames);

  }

}

7 0
4 years ago
PLEASE SOMEONE ANSWER THIS
GuDViN [60]

Answer:

Any of these?

Explanation:

1147. 4117. 7411

1471. 4171

1714. 4711

1741. 7114

1417. 7141

5 0
3 years ago
Read 2 more answers
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