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Vlad [161]
2 years ago
9

What were the names of Henry VIII's six wives?

Computers and Technology
2 answers:
timurjin [86]2 years ago
7 0

Answer:

Jane Seymour,Anne Boleyn,Katherine of Aragon,Anne of Cleves,Katherine Howard,Katherine Parr

Explanation:

RSB [31]2 years ago
5 0

Answer:

Divorced, beheaded, died...
Divorced, beheaded, survived...

Welcome to the show, to the historemix

Switching up the flow as we add the prefix

Everybody knows that there used to be six wives

Raising up the roof 'til we hit the ceiling

Get ready for the truth that we'll be revealing

Everybody knows that we used to be six wives

Now they're, EX-WIVES!
Catherine of Aragon.
Anne Boleyn

Jane Seymour

Anne of Cleves

Catherine Howard

Katherine Parr
EX-WIVES!

Explanation:

I always listened to six the musical, which tells the story of all the six wives, at the end of the answer you'll find all of them, this is just the beginning of Six Wives - The song, listen to it, and the whole soundtrack; It'll help you understand more!

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In a C++ program, one and two are double variables and input values are 10.5 and 30.6. After the statement cin >> one >
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Answer:

variable one stores 10.5 and two stores 30.6

Explanation:

In c++ language, the cout keyword is used to write to the standard output. The input from the user is taken by using the cin keyword.

For the input from the user, a variable need is declared first.

datatype variable_name;

The input can be taken one at a time as shown.

cin >> variable_name;

The input for more than one variable can be taken in a single line as given by the syntax below.

1. First, two variables are declared.

datatype variable_name1, variable_name2;

2. Both input is taken simultaneously as shown.

cin >> variable_name1, variable_name2;

For the given scenario, two double variables are declared as below.

double one, two;

The question mentions input values for the two double variables as 10.5 and 30.6.

3. The given scenario takes both the values as input at the same time, in a single line as shown below.

cin >> one >> two;

4. After this statement, both the values entered by the user are accepted.

The values should be separated by space.

First value is stored in the variable one.

Second value is stored in the variable two.

5. The user enters the values as follows.

10.5 30.6

6. The value 10.5 is stored in variable one.

7. The value 30.6 is stored in variable two.

The c++ program to implement the above is given below.

#include <iostream>

using namespace std;

int main() {

   double one, two;      

   cout << " Enter two decimal values " << endl;

   cin >> one >> two;

   cout << " The input values are " << endl;

   cout << " one : " << one << " \t " << " two : " << two << endl;

   return 0;

}

OUTPUT

Enter two decimal values  

10.5 30.6

The input values are  

one : 10    two : 530.6

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Two character strings may have many common substrings. Substrings are required to be contiguous in the original string. For exam
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Answer:

Explanation:

The following function is written in Java. It takes two strings as parameters and calculates the longest substring between both of them and returns that substring length.

import java.util.*;

class Test

{

   public static void main(String[] args)

   {

       String X = "photograph";

       String Y = "tomography";

       System.out.println(X + '\n' + Y);

       System.out.println("Longest common substring length: " + longestSub(X, Y));

   }

   static int longestSub(String X, String Y)

   {

       char[] word1 = X.toCharArray();

       char[] word2 = Y.toCharArray();

       

       int length1 = X.length();

       int length2 = Y.length();

       int substringArray[][] = new int[length1 + 1][length2 + 1];

       int longestSubstringLength = 0;

       

       for (int i = 0; i <= length1; i++)

       {

           for (int j = 0; j <= length2; j++)

           {

               if (i == 0 || j == 0)

                   substringArray[i][j] = 0;

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               {

                   substringArray[i][j]

                           = substringArray[i - 1][j - 1] + 1;

                   longestSubstringLength = Integer.max(longestSubstringLength,

                           substringArray[i][j]);

               }

               else

                   substringArray[i][j] = 0;

           }

       }

       return longestSubstringLength;

   }

}

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