Answer:
The pattern is this: I create a function p(x) such that
p(1)=1
p(2)=1
p(3)=3
p(4)=4
p(5)=6
p(6)=7
p(7)=9
Therefore, trivially evaluating at x=8 gives:
p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)
Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.
Step-by-step explanation:
Answer:
5,976 workers
Step-by-step explanation:
498 times 12 = 5976
Answer:
6. 5 % is the answer
Step-by-step explanation:
formula =
<em>R</em><em> </em><em>=</em><em> </em><em>I</em><em> </em><em>×</em><em> </em><em>1</em><em>0</em><em>0</em><em> </em><em>/</em><em> </em><em>P</em><em> </em><em>×</em><em> </em><em>T</em>
Answer:
75% of the data will reside in the range 23000 to 28400.
Step-by-step explanation :
To find the range of values :
We need to find the values that deviate from the mean. Since we want at least 75% of the data to reside between the range therefore we have,
Solving this, we would get k = 2 which shows the value one needs to find lies outside the range.
Range is given by : mean +/- (z score) × (value of a standard deviation)
⇒ Range : 25700 +/- 2 × 1350
⇒ Range : (25700 - 2700) to (25700 + 2700)
Hence, 75% of the data will reside in the range 23000 to 28400.