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Taya2010 [7]
3 years ago
7

Give the answer and explain, please!

Mathematics
1 answer:
Dimas [21]3 years ago
8 0

Answer:

The total yearly cost is $300 at each gym for 50 visits.

Step-by-step explanation:

Healthy Gym: 6n = t

Fitness Gym: 50 + 5n = t

When n = 50 visits, then...

Healthy Gym: 6(50) = $300

Fitness Gym: 50 + 5(50) = $300

You might be interested in
-7q + 12r = 3q - 4r what dose r equal
Elanso [62]

Answer:

r = 5y/8

Step-by-step explanation:

isolate the variable by dividing each side by factors that contain the variable.

6 0
3 years ago
Otto invests $1,000 at age 20. Otto wants theinvestment to be worth $4,000 by age 30. Ifinterest is compounded continuously, wha
AveGali [126]
r\approx0.139

1) Since this is a Continuously Compounded operation in a 10 yrs period, then we can write out the following equation:

\begin{gathered} A=Pe^{rt} \\  \end{gathered}

2) Plugging into the equation the given data and since Otto is 20 yrs old and he plans to get $4,000 in ten years, we can write out:

\begin{gathered} 4000=1000e^{\mleft\{10r\mright\}} \\ \frac{4000}{1000}=\frac{1000e^{10r}}{1000} \\ 4=e^{10r} \\ \ln (4)=\ln (e)^{10r} \\ 10r=\ln (4) \\ r=\frac{\ln (4)}{10} \\ r=0.1386 \end{gathered}

3) Thus the rate Otto needs is

r=0.1386\approx0.139

Note that since the 0.1386 the six here is greater than 5 then we can round up to the next thousandth, in this case: 0.139. For the 0.1386 is closer to 0.139 (0.004) than to 0.138 (0.006).

Or 13.9%

8 0
1 year ago
Arrange the systems of equations that have a single solution in Increasing order of the x-values in their solutions.
NemiM [27]

Complete question is;

Arrange the systems of equations that have a single solution in Increasing order of the x-values in their solutions.

1) 2x + y = 10

x - 3y = -2

2) x + 2y = 5

2x + y = 4

3) x + 3y = 5

6x - y = 11

4) 2x + y = 10

-6x - 3y = -2

Answer:

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

Step-by-step explanation:

1) 2x + y = 10 - - - (eq 1)

x - 3y = -2 - - - (eq 2)

Multiply eq 1 by 3 to get;

6x + 3y = 30

Add it to eq 2 to get;

7x = 28

x = 28/7

x = 4

2) x + 2y = 5 - - - (eq 1)

2x + y = 4 - - - (eq 2)

Multiply eq 2 by 2 to get;

4x + 2y = 8

Subtract eq 1 from it to get;

3x = 3

x = 3/3

x = 1

3) x + 3y = 5 - - - (eq 1)

6x - y = 11 - - - (eq 2)

Multiply eq 2 by 3 to get;

18x - 3y = 33

Add to eq(1) to get;

19x = 38

x = 38/19

x = 2

4) 2x + y = 10 - - - (eq 1)

-6x - 3y = -2 - - - (eq 2)

Make y the subject in eq 1 to get;

y = 10 - 2x

Put in eq (2);

-6x - 3(10 - 2x) = -2

-6x - 30 + 6x = -2

0 = 0

Thus,no solution exists.

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

3 0
3 years ago
*BRAINLIEST* (Easy Question: Warm UP) Find a positive solution to each equation: x2 = 9/4?
prisoha [69]

Answer:

<u>A</u>

Step-by-step explanation:

<u>Given</u>

  • x² = 9/4

<u>Solving</u>

  • Take the square root on both sides
  • √x² = √9/4
  • ⇒ x = 3/2
  • <u>Option A is the correct option.</u>
7 0
2 years ago
Read 2 more answers
On each 3 days derrik rode 6.45 km to school, 150 meters to the library, and then 500 meters back home. How many kilometers did
Andrew [12]

Just add all 3 numbers up together:

6.45+ 0.15+0.5

=7.1

Since it was three days multiply the 7.1 by three

=7.1x3

=24 

So for three days derrick rode for 24 km 

Hoped I helped :)

7 0
3 years ago
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