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4 years ago

Give the answer and explain, please!

Mathematics

1 answer:

Dimas [21]4 years ago

8 0

Answer:

The total yearly cost is $300 at each gym for 50 visits.

Step-by-step explanation:

Healthy Gym: 6n = t

Fitness Gym: 50 + 5n = t

When n = 50 visits, then...

Healthy Gym: 6(50) = $300

Fitness Gym: 50 + 5(50) = $300

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Please finish this equation and write the answer

olga55 [171]

Given:

The equation is:

$2540=\dfrac{22}{7}r^2(20)$

To find:

The solution for the given equation.

Solution:

We have,

$2540=\dfrac{22}{7}r^2(20)$

It can be written as:

$\dfrac{2540\times 7}{22\times 20}=r^2$

$\dfrac{17780}{440}=r^2$

$\dfrac{889}{22}=r^2$

Taking square root on both sides, we get

$\sqrt{\dfrac{889}{22}}=r$ [Radius cannot be negative]

$r=6.3568145$

$r\approx 6.36$

Therefore, the value of r is about 6.36 cm.

7 0

3 years ago

Angle A and angle B are supplementary. The measure of angle B is 82.5.

stealth61 [152]

Answer:

Angle A = 97.5º

Step-by-step explanation:

Supplmentary means 2 angles that equal 180º. So we already have 1 angle, so now all we have to do is subtract 82.5 from 180.

180 - 82.5 = 97.5

5 0

3 years ago

Read 2 more answers

Lebo buys blank writable CDs in bulk. He repackages them and sells them

Kay [80]

Answer:

He must sell each CD for R1,10 to make 40% profit

Step-by-step explanation:

R40×5%=2

R40-2=R38

40%×38=R15,2

15,2+40=55,2

55,2÷50=R1,10

i didnt do the radio sum...

5 0

3 years ago

A polynomial function has a zero at 4 (multiplicity 3) and 0 (multiplicity 1). Write a function in standard form that can repres

VLD [36.1K]

Answer:

(x^4) - 64x

Step-by-step explanation:

zeros at 4 and 0 are the roots so can be factor as x*(x-4) and the multiplicity tels to what power you have to raise those factors

$x^{1} *(x-4)^{3}$ becuase multiplicity of 1 for root at 0, and multiplicity of 3 at root 4

now to write this in standard form

$x*(x-4)^{3} = \\x*(x-4)(x^{2} +4x+16)= \\(x^{2} -4x)(x^{2} +4x+16) = \\x^{4} +4x^{3} +16x^{2} -4x^{3} -16x^{2} -64x = \\x^{4} -64x$

8 0

3 years ago

..................................

yanalaym [24]

Answer:

The answer is a² .

Step-by-step explanation:

You have to substitute x and y into the expression :

$let \: x = a \cos(θ) \\ let \: y = a \sin( θ)$

${x}^{2} + {y}^{2} = {(a \cosθ )}^{2} + {(a \sinθ) }^{2}$

${x}^{2} + {y}^{2} = {a}^{2}( {cos}^{2}θ) + {a}^{2} ({sin}^{2}θ)$

Next, you have to apply Basic Trigonometric Identity :

${sin}^{2} θ + {cos}^{2} θ = 1$

${x}^{2} + {y}^{2} = {a}^{2} ( {cos}^{2} θ + {sin}^{2} θ)$

${x}^{2} + {y}^{2} = {a}^{2} (1)$

${x}^{2} + {y}^{2} = { a}^{2}$

8 0

3 years ago