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3 years ago

Multiply.

Mathematics

1 answer:

Lena [83]3 years ago

6 0

<span>(4.214) x (3.06) = 12.89484 and can be rounded up to 12.9</span>

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It takes Prakash 2 1/2 hours to paint a medium sized room. If he can work 50 minutes each day, how many days will it take to com

Aleksandr-060686 [28]

60 min in one hour so 60+60+30=150.
150 divided 50 mins = 3 days (50+50+50=150)

3 0

4 years ago

You

saul85 [17]

Answer:

$29,005.97

Step-by-step explanation:

Cn = Co * (1 + i)^n

Cn = 104,986.99(1+.05/1)^(1*5)

Cn = 104,986.99(1+.05)^5

Cn = 104,986.99(105)^5

Cn = 104,986.99(1.2763)

Cn = 133,992.96, total money at end

133,992.96-104,986.99= $29,005.97, interest accumulated

4 0

3 years ago

Mr Davis is creating a spice mixture for a recipe.2/5 of the spice mixture was oregano 1/3 of the spice mixture was basil the re

attashe74 [19]

Answer: $\frac{11}{15}$

Step-by-step explanation:

You know that:

- 2/5 of the spice mixture was oregano.

- 1/3 of the spice mixture was basil.

Then, to find the fraction of the total amount of spice mixture that was oregano and basil, you must add both fractions, as following:

- Find the least common multiply of the denominators:

$LCM=5*3=15$

- Divide the LCM by each original denominator and multiply the result by each numerator.

- Make the addition.

Then, the result is:

$\frac{(2*3)+(1*5)}{15}=\frac{6+5}{15}=\frac{11}{15}$

7 0

3 years ago

Ariel wrote a total of 4 pages over 2 hours. How many hours will Ariel have to spend writing this week in order to have written

Pachacha [2.7K]

Your answer is 1

Step-by-step explanation:

4=2

8=?

4÷8×2

3 0

3 years ago

Find the volume of the solid.

dmitriy555 [2]

In Cartesian coordinates, the region (call it $R$ ) is the set

$R = \left\{(x,y,z) ~:~ x\ge0 \text{ and } y\ge0 \text{ and } 2 \le z \le 4-x^2-y^2\right\}$

In the plane $z=2$ , we have

$2 = 4 - x^2 - y^2 \implies x^2 + y^2 = 2 = \left(\sqrt2\right)^2$

which is a circle with radius $\sqrt2$ . Then we can better describe the solid by

$R = \left\{(x,y,z) ~:~ 0 \le x \le \sqrt2 \text{ and } 0 \le y \le \sqrt{2 - x^2} \text{ and } 2 \le z \le 4 - x^2 - y^2 \right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\sqrt2} \int_0^{\sqrt{2-x^2}} \int_2^{4-x^2-y^2} dz \, dy \, dx$

While doable, it's easier to compute the volume in cylindrical coordinates.

$\begin{cases} x = r \cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \end{cases} \implies \begin{cases}x^2 + y^2 = r^2 \\ dV = r\,dr\,d\theta\,d\zeta\end{cases}$

Then we can describe $R$ in cylindrical coordinates by

$R = \left\{(r,\theta,\zeta) ~:~ 0 \le r \le \sqrt2 \text{ and } 0 \le \theta \le\dfrac\pi2 \text{ and } 2 \le \zeta \le 4 - r^2\right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\pi/2} \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta \, dr \, d\theta \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta\,dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} r((4 - r^2) - 2) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} (2r-r^3) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \left(\left(\sqrt2\right)^2 - \frac{\left(\sqrt2\right)^4}4\right) = \boxed{\frac\pi2}$

3 0

1 year ago