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Y_Kistochka [10]

3 years ago

10

Helpme please i dont understand this

2 answers:

Fiesta28 [93]3 years ago

6 0

Answer:

1. Distributive Property

2. Commutative Property

3. Associative Property

4. Distributive Property

Sorry if any of these are wrong!

irinina [24]3 years ago

3 0

Answer: Distributive, Associative, Commutative, Distributive

Step-by-step explanation: you are asking for the second one. It is the associative property like I mentioned earlier because you are moving the paranthesis (only applies for multiplication and addition) and therefore associating the terms of the problem together

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Gabriella is x years old. Her sister, Felicia, is six years older than she is. Their mother is twice as old as Felicia. Their au

Yuri [45]

G = x
Felicia is Gabriella's age + 6
F = x + 6
Their mother is twice Felicia's age
M = 2(x + 6) or 2x + 12
Tanya is the age of their mother plus Gabriella's age
A = 2x + 12 + x = 3x + 12
3x + 12

7 0

4 years ago

Help look at picture ;-;

GaryK [48]

Answer:

Step-by-step explanation:

turn the 4/3 into a decimal.=1.33

multiply 1.33*3.14=4.1762

i cant see the rest is it r³?

4 0

3 years ago

Product of (x – 3)(2x + 1)?

Arada [10]

Answer:

If you need the expression: 2x^2-5x-3

If you need answers from a factored form: x=3 and x= -1/2

Step-by-step explanation:

(x-3)(2x+1)

2x^2+x-6x-3

2x^2-5x-3

3 0

3 years ago

On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John

insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

$H_{max}=\frac{v^2}{2g}$

$H_{max} = \frac{(48)^2}{2 \times 12}$

= 96 ft

b). Time he can stay in the air before hitting the ground is

$T=\frac{2v}{g}$

$T=\frac{2 \times 48}{12}$

= 8 seconds

c). Considering upward motion as positive direction.

v = u + at

We find the time taken to reach the maximum height by taking v = 0.

v = u + at

0 = 16 + (12) t

$t=\frac{16}{12}$

$=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t = $=\frac{4}{3} \ s$ , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$ feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0

3 years ago

Please answer this question :)

Scorpion4ik [409]

Answer:

5.2692307692307692307692307692308

Step-by-step explanation:

hope this helps! :)

5 0

3 years ago

Read 2 more answers