L×w=64 ft^2...(1)
2w+8= l...(2)
l=64-w...(1a)
2w+8= 64-w
2w+w+8=64
3w=64-8
3w÷3= 56÷3
w=18.6'
l×w= 64
l×18.6= 64
l= 64÷18.6
l= 3.44 to the nearest hundredths.
At noon, the temperature was 36 degrees. At midnight, the temperature was 30 degrees. By 6:00 am it drooped 5 degrees. Since it dropped 5 degrees, you subtract 5 from 30, which equals 25. It then increased by 11 degrees. Since the temperature increased, you add 11 to 25, which equals 36. At noon, the temperature was 36 degrees.
Well first you have to figure out what you need to solve. then you write out the two equations and solve the system s from there
Hope this helps! Answer: k = 2f/p
Answer:
Hey there!
I would prefer method two.
Both methods give the right solution, but method two is more straightforward. Instead of distributing, you simply divide and don't need to do as much work.
Let me know if this helps :)
