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Rzqust [24]
3 years ago
12

Can I please get some help on these 2 problems? Thank you. pictures attached.

Mathematics
1 answer:
Hoochie [10]3 years ago
7 0
My answer is the first one

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Some sales positions pay a commission if sales exceed a set quota. Yolanda Gonzalez is paid $2,000 per month plus a commission o
max2010maxim [7]
It would be $2000 for that month.
4 0
3 years ago
The probability that a new advertising campaign will increase sales is assessed as being 0.80. The probability that the cost of
tatuchka [14]

Answer:

The probability that the cost is kept within budget or the campaign will increase sales is 0.88

Step-by-step explanation:

The probability that the cost is kept within budget (event A) <u>or</u> the campaign will increase sales (event B) is the <u>union</u> of the probability of those two events. By basic properties of probability, this is:

P(A ∪ B) = P(A) + P (B) - P(A ∩ B)

and for independent events:

P(A ∩ B) = P(A) * P(B)

So:

P(A ∪ B) = 0.80 + 0.40 - (0.80*0.40) = 1.20 - 0.32 = 0.88

5 0
3 years ago
(a+b)2 ;a=1/2 and b=2
FrozenT [24]

Answer:

\frac{25}{4}

Step-by-step explanation:

a + b = \frac{1}{2} + 2 = 2 \frac{1}{2} = \frac{5}{2}, thus

(a + b)² = (\frac{5}{2} )² = \frac{5}{2} × \frac{5}{2} = \frac{5(5)}{2(2)} = \frac{25}{4}

8 0
3 years ago
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I don’t know how to do this:(
Wewaii [24]

Answer:

me niether

Step-by-step explanation:

lol

4 0
3 years ago
Radioactive Decay Beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining
Flura [38]

Answer:

the equation should be corrected to fit the data of the problem.  With the corrected equation a mass of 0.5 grams remains after 150 years

Step-by-step explanation:

for the mass y( in grams)

y=23* (1/2)^(t/45), t ≥ 0.

the initial mass is at t=0 , then

y= 23 grams  → should be 16 grams

half-life from the equation = 45 years → should be 30 years

the correct equation should be

y=16*(1/2)^(t/30), t ≥ 0

then after 150 years  → t= 150

y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams

then a mass of 0.5 grams remains after 150 years

5 0
3 years ago
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