$we \: have \: 5x + 6x + y + y + 3y + 4 + 6 + 2 \\ x \: terms = 5x + 6x = 11x \\ y \: terms = y + y + 3y = 5y \\ constant = 4 + 6 + 2 = 12 \\ then \: 11x + 5y + 12 \\ option \: (c) \\ thank \: you$

7 0

3 years ago

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a high school play costs an up front $3000 to produce plus an additional cost of each performance. Every sold-out performance of

vodomira [7]

So based on the information here, it costs $3,000 up front but an additional $1,000 for each play and each sold out performance brings in $2,500

For the sake of simplicity, when solving it, I won't be putting the dollar sign

So the equation is the following:

3,000+1,000x=2,500x

So you need to get "x" by itself

First, minus 1,000x from each side

So it is now 3,000=1,500x

Now you divide 3,000 by 1,500 which is 2

x=2

So that means two performances need to sell out in order to break even with the cost

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To check:

$3,000+$1,000(2)=$2,500(2)

$1,000×2=$2,000 and $3,000+$2,000=$5,000

$5,000=$2,5000(2)

$2,500×2=$5,000

$5,000=$5,000

So it it correct

5 0

3 years ago