Question

How many milliequivalents of sodium chloride are contained with 3 L of normal saline?

Answer 1

Answer:

466mEq

Step-by-step explanation:

First, we need to know the concentration of NaCl in a normal saline solution, this is by definition 0.9%, meaning we have 0.9g of NaCl per 100ml of solution, we want to know how much NaCl we have in 3L (3000ml):

$3000ml*\frac{0.9g}{100ml}=27g=27000mg$

So, we have 27000mg in 3L of normal saline solution.

Now, acording to our milliequivalent (mEq) equation ($mEq=\frac{mg}{pE}$) where pE is de molecular mass of NaCl divided by their charges, in this case 1:

$pE= \frac{23+35}{1}=\frac{58}{1} = 58$

Finally we substitute in the mEq formula:

$mEq=\frac{mg}{pE}=\frac{27000}{58}=466mEq$

I hope you find this information useful! Good luck!