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Delicious77 [7]
2 years ago
10

6 men and 8 women are going to be assigned to a specific row of seats in a theater. If the 14 tickets for the numbered seats are

given out at random, find the probability that exactly one womb is in one of the first 5 seats.
Mathematics
1 answer:
Sedbober [7]2 years ago
8 0
If exactly one woman is to sit in one of the first 5 seats, then it means that 4 men completes the first 5 seats.
No of ways 4 men can be selected from 6 men = 6C4 = 15
No of ways 4 men can sit on 5 seats = 5P4 = 120
No of ways 1 woman can be selected fom 8 women = 8C1 = 8
No of ways 1 woman can sit on 5 seats = 5P1 = 5

No of ways <span>that exactly one woman is in one of the first 5 seats = 15 * 120 * 8 * 5 = 72,000

No of ways 14 people can be arranged in 14 seats = 14!

Probability that exactly one woman is in one of the first 5 seats = 72,000 / 14! = 0.0000008259 = 0.000083%
</span>
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(3x2 + 10x + 3) by (x + 3)​
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Explanation: 3 x 2 + 10 x + 3 We can Split the Middle Term of this expression to factorise it. In this technique, if we have to factorise an expression like a x 2 + b x + c , we need to think of 2 numbers such that: N 1 ⋅ N 2 = a ⋅ c = 3 ⋅ 3 = 9 and, N 1 + N 2 = b = 10 After trying out a few numbers we get: N 1 = 9 and N 2 = 1 9 ⋅ 1 = 9 , and 9 + ( 1 ) = 10 3 x 2 + 10 x + 3 = 3 x 2 + 9 x + 1 x + 3 = 3 x ( x + 3 ) + 1 ( x + 3 ) ( 3 x + 1 ) ( x + 3 ) is the factorised form for the expression.

c
, we need to think of 2 numbers such that:
N
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2
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a
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3
⋅
3
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9

and,
N
1
+
N
2
=
b
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After trying out a few numbers we get:
N
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=
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and
N
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1

9
⋅
1
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+
(
1
)
=
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3
x
2
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10
x
+
3
=
3
x
2
+
9
x
+
1
x
+
3

=
3
x
(
x
+
3
)
+
1
(
x
+
3
)
(
3
x
+
1
)
(
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is the factorised form for the expression.
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2 years ago
How do i solve this question
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Answer:

a\frac{c}{8\pi  b}

Step-by-step explanation:

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\frac{8\pi ab}{8\pi b} =\frac{c}{8\pi b}

Simplify:

a\frac{c}{8\pi  b} ; a\frac{c}{8\pi  b}; b\neq 0

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