A- 53
B- 53
C- 127
D- 54
E- E+20
F- 59
Can you please elaborate? I need to know if there are any flat fees and what the price of A is.
Here is an example though: florist C charges $3.00 a rose and a fee of $8.00 for delivery. Florist D charges $2.00 a rose and a delivery fee of $5.00.
If florist D marks up their price to $4.00 a rose, then when would it be cheaper to buy from florist C?
It would be cheaper to buy from florist C if you buy 4 or more roses.
The cost would be the same if you bought 3 roses.
Remember, this is just an example. Glad to help though! :)
Answer:
The quadratic mean of 2 real positive numbers is greater than or equal to the arithmetic mean.
Step-by-step explanation:
x and y Quadratic Mean Arithmetic mean
3 and 3 3 3
2 and 3 2.55 2.5
3 and 6 4.74 4.5
2 and 5 3.8 3.5
2 and 17 12.1 9.5
18 and 28 23.5 23
10 and 48 34.7 29
The quadratic mean is always greater than the arithmetic mean except when x and y are the same.
When the difference between the pairs is small the difference in the means is also small. As that difference increases the difference in the means also increases.
So we conjecture that the quadratic mean is always greater than or equal to the arithmetic mean.
Proof.
Suppose it is true then:
√(x^2 + y^2) / 2) ≥ (x + y)/2 Squaring both sides:
(x ^2 + y^2) / 2 ≥ (x + y)^2 / 4 Multiply through by 4:
2x^2 +2y^2 ≥ (x + y)^2
2x^2 +2y^2 >= x^2 + 2xy + y^2
x^2 + y^2 >= 2xy.
x^2 - 2xy + y^2 ≥ 0
(x - y)^2 ≥ 0
This is true because the square of any real number is positive so the original inequality must also be true.
Answer: This is either a trick question or real, but round it to the nearest thousanth I guess.
