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konstantin123 [22]
3 years ago
12

3. Diego drew a scaled version of a Polygon P and labeled it Q.

Mathematics
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

The scale factor used to go from P to Q is 1/4

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x -----> area of polygon Q

y -----> area of polygon P

z^{2}=\frac{x}{y}

we have

y=72\ units^2

Find the area of polygon Q

Divide the the area of polygon Q in two triangles and three squares

The area of the polygon Q is equal to the area of two triangles plus the area of three squares

see the attached figure N 2

Find the area of triangle 1

A=(1/2)(1)(2)=1\ units^2

Find the area of three squares (A2,A3 and A4)

A=3(1)^2=3\ units^2

Find the area of triangle 5

A=(1/2)(1)(1)=0.5\ units^2

The area of polygon Q is

x=1+3+0.5=4.5\ units^2

Find the scale factor

z^{2}=\frac{x}{y}

we havey=72\ units^2

x=4.5\ units^2

substitute and solve for z

z^{2}=\frac{4.5}{72}

z^{2}=\frac{1}{16}

square root both sides

z=\frac{1}{4}

therefore

The scale factor used to go from P to Q is 1/4

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Answer: (x + 6)² + (y + 5)² = 17

Explanation:

1)  The equation of a circle is: (x - a)² + (y - b)² = r², wnere:
a is the x-coordinate of the center of the circleb is the y-coordinate of the center of the circler is the radius of the circle
2) Since the points (-7,-1) and (-5,9) define a diameter, you can find the center of the circle as the mid point of the diameter:
x-coordinate of the mid point = (-7 - 5) / 2 = - 12 / 2 = - 6
y-coordinate of the mid point = (-9 - 1)/ 2 = - 10 / 2 = - 5

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3) The radius of the center is half the diameter.
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diameter² = (7 - 5)² + (- 1 + 9)² = 2² + 8² = 4 + 64 = 68

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⇒ radius = diamter / 2 = 2√17 / 2 = √17

4) Now you can replace the coordinates of the center and the radius into the equation:
(x + 6)² + (y + 5)² = 17


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