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3 years ago

Given F(x) =3x^2 - 4 and F(a) = 8 find a

1 answer:

5 0

$F(x)=3x^2-4\\\\F(a)=8\to3a^2-4=8\qquad\text{add 4 to both sides}\\\\3a^2=12\qquad\text{divide both sides by 3}\\\\a^2=4\to a=\pm\sqrt4\to a=\pm2\\\\Answer:\ \boxed{A.\ \pm2}$

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elixir [45]

Your answer is D hope this helps!!

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3 years ago

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Can someone help me solve (a) and (c) pls.<br>Thanks

Alex777 [14]

Answer:

Area of ABCD = 959.93 units²

Step-by-step explanation:

a). By applying Sine rule in the ΔABD,

$\frac{\text{SinA}}{46}=\frac{\text{Sin}\angle{DBA}}{35}$

$\frac{\text{Sin110}}{46}=\frac{\text{Sin}\angle{DBA}}{35}$

Sin∠DBA = $\frac{35\times \text{Sin}(110)}{46}$

m∠DBA = $\text{Sin}^{-1}(0.714983)$

m∠DBA = 45.64°

Therefore, m∠ADB = 180° - (110° + 45.64°) = 24.36°

m∠ADB = 24.36°

c). Area of ABCD = Area of ΔABD + Area of ΔBCD

Area of ΔABD = AD×BD×Sin( $\frac{24.36}{2}$ )

= 35×46Sin(12.18)

= 339.68 units²

Area of ΔBCD = BD×BC×Sin( $\frac{59.92}{2}$ )°

= 46×27×(0.4994)

= 620.25 units²

Area of ABCD = 339.68 + 620.25

= 959.93 units²

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4 years ago

Oop- help me;-;<br> please..

VMariaS [17]

Answer:
5c+4=2(c-5)
opening the parentheses we get:
5c+4=2c-10
putting like terms together we get
5c-2c=-10-4
3c=-14
c=-14/3

so the answer would be A. C = - 4 2/3

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