At what value(s) of x does f(x) = -x^4 + 2x^2 have a relative maximum? (4 points)
1 answer:
Take the derivitive
f'(x)=-4x^3+4x
find where it equals 0
0=-4x(x^2-1)
0=-4x(x-1)(x+1)
at x=-1, 0, 1
those are critical points
put those on number line
test points between to see if positive or negative
f'(-2)=(+)
f'(-0.5)=(-)
f'(0.5)=(+)
f'(2)=(-)
see attachment
remember the max is where the slope changes from positive to negative
at -1 and 1 only
f'(x)=-4x^3+4x
find where it equals 0
0=-4x(x^2-1)
0=-4x(x-1)(x+1)
at x=-1, 0, 1
those are critical points
put those on number line
test points between to see if positive or negative
f'(-2)=(+)
f'(-0.5)=(-)
f'(0.5)=(+)
f'(2)=(-)
see attachment
remember the max is where the slope changes from positive to negative
at -1 and 1 only
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(a)
(b)
(c) At 4 weeks, when both will be seeing an average of 3 hours of TV.
Step-by-step explanation:
a) For the students, they start at X(0)=5 h and ΔX=-0.5 h/week.
We can write
b) For the professors, they start at X(0)=1 h and ΔX=+0.5 h/week.
We can write
c) The seew which they will be watching the same amount of hours will be the 4th week.
The amount of hours will be