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a_sh-v [17]
3 years ago
14

Explain how you can find the opposite of the opposite of any number without using a number line

Mathematics
1 answer:
liberstina [14]3 years ago
4 0
Just make that number negative to find the opposite but the opposite of the negative number is going to be the original number again.
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5q greater than or equal to 8q -3/2
kakasveta [241]

5q ≥ 8q - 3/2

<em><u>Add 3/2 to both sides.</u></em>

3/2 + 5q ≥ 8q

<em><u>Subtract 5q from both sides.</u></em>

3/2 ≥ 3q

<em><u>Multiply both sides by 2.</u></em>

3 ≥ 6q

<em><u>Divide both sides by 6.</u></em>

0.5 ≥ q.

The value of q is less than or equal to 0.5.

8 0
3 years ago
Brianna is getting materials for a chemistry experiment. Her teacher gives her a container that has 0.25 liter of a liquid in it
IgorC [24]

Answer: 0.1 liter

Step-by-step explanation:

From the question, we are informed that Brianna teacher gives her a container that has 0.25 liter of a liquid in it and she needs to use 0.4 of this liquid for the experiment.

The amount of liquid that Brianna will use will be:

= 0.4 × 0.25 liters

= 0.1 liter

6 0
3 years ago
Evaluate the integral. W (x2 y2) dx dy dz; W is the pyramid with top vertex at (0, 0, 1) and base vertices at (0, 0, 0), (1, 0,
In-s [12.5K]

Answer:

\mathbf{\iiint_W (x^2+y^2) \ dx \ dy \ dz = \dfrac{2}{15}}

Step-by-step explanation:

Given that:

\iiint_W (x^2+y^2) \ dx \ dy \ dz

where;

the top vertex = (0,0,1) and the  base vertices at (0, 0, 0), (1, 0, 0), (0, 1, 0), and (1, 1, 0)

As such , the region of the bounds of the pyramid is: (0 ≤ x ≤ 1-z, 0 ≤ y ≤ 1-z, 0 ≤ z ≤ 1)

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \int ^{1-z}_0 \int ^{1-z}_0 (x^2+y^2) \ dx \ dy \  dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \int ^{1-z}_0 ( \dfrac{(1-z)^3}{3}+ (1-z)y^2) dy \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0  \ dz \  ( \dfrac{(1-z)^3}{3} \ y + \dfrac {(1-z)y^3)}{3}] ^{1-x}_{0}

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0  \ dz \  ( \dfrac{(1-z)^4}{3}+ \dfrac{(1-z)^4}{3}) \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz =\dfrac{2}{3} \int^1_0 (1-z)^4 \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz =- \dfrac{2}{15}(1-z)^5|^1_0

\mathbf{\iiint_W (x^2+y^2) \ dx \ dy \ dz = \dfrac{2}{15}}

7 0
3 years ago
What is the value of x?
Blizzard [7]

check the picture below.

so, when we have a line from a 90° angle running perpendicular to the opposite side, like in this case, we end up with three similar triangles, a large one containing the other two, a medium and a small one.

now, using the sides proportions as you see there, of the small and large one, we get that much.

3 0
3 years ago
How to do -7x-3x+2=8x-8
zavuch27 [327]
<span><span>If you would like to solve the equation </span>- 7 * x - 3 * x + 2 = 8 * x - 8, you can calculate this using the following steps:<span>

- 7 * x - 3 * x + 2 = 8 * x - 8
- 7 * x - 3 * x - 8 * x = - 8 - 2
- 18 * x = - 10    /(-18)
x = 10 / 18
x = 5/9

<span>The correct result would be </span>5/9<span>.</span></span></span>
7 0
3 years ago
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