Answer:
1st is alst, 2nd is third, third is first, last is second
Explanation:
Tolerance towards cold temperature and adaptabilities are the variation that help the trout fish to survive.
<h3>Which factor help the trout to survive?</h3>
If temperatures fall over time because of climate change, the tolerance towards cold temperature is the one variation that would likely help the trout to survive because only those organisms survive in cold temperature that have good tolerance and various adaptation towards cold temperature.
So we can conclude that tolerance towards cold temperature and adaptabilities are the variation that help the trout fish to survive.
Learn more about trout here: brainly.com/question/13950000
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<h2>Answer</h2><h2>A. helical</h2><h2>
</h2><h2>
Explanation:</h2>
<span>Serum potassium, phosphate, calcium
and magnesium concentrations will not directly suggest intrarenal acute renal
failure. The confirmatory test for acute renal failure is the ratio of serum
creatinine and blood urea nitrogen (BUN). </span>They serve as indicators of decrease
renal function when there is a small amount of waste products primarily blood
urea nitrogen and creatinine found in the blood of the patient. Moreover, the
decline measurement of these two serum in the blood will be use for the
diagnosis of intrarenal acute renal failure.
Answer:
1,250,000 shrimps per m³
Explanation:
Population density refers to how dense an area is per unit area/volume, and it is calculated by dividing the number of individuals in that area (population) by the area/volume of that area. That is;
Population density = population (N)/volume
According to this question, a certain lake has a volume of about 480 m³ that harbors a 600 million of freshwater shrimp. This means that;
Population density of the lake = population of shrimps ÷ volume of lake
Population density = 600,000,000 ÷ 480
Population density = 1,250,000 shrimps per m³
