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Art [367]
3 years ago
13

A rhombus has diagonals 500 yd and 800 yd in length. Find the area in square miles.

Mathematics
1 answer:
nordsb [41]3 years ago
8 0
We know that
<span>A simple formula for the area of a rhombus when you know the lengths of the diagonals is half the product of the diagonals
</span>
Area=d1*d2/2
d1=500 yd
d2=800 yd

1 mile is equal to -----> 1760 yd
x mile---------------> 500 yd
x=500/1760----> x=0.2841 mi

1 mile is equal to -----> 1760 yd
x mile---------------> 800 yd
x=800/1760----> x=0.4545 mi

Area=(0.2641*0.4545)/2-----> 0.06 miles²

the answer is
0.06 miles²
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SOMEONE PLS HELP!! its due in 10 minutes
melisa1 [442]

Answer:

option 2 is better( 3 pizza with 30 inches diameter)

Step-by-step explanation:

Area of the large pizza = A=πr^2=962.11 * 2( for two pizzas)=1924.22

Area for small pizza : A=πr^2=706.86*3 pizza=2120.58

your buying more pizza for less price

(there are more than one way to figure the answer)

3 0
3 years ago
One side of a rectangle is 20 cm larger than the other side. If you make the smaller side two times larger and the larger side t
grandymaker [24]
Let L be the length
Let w be the width
Let p be the perimeter
L+w+L+w=p
L=w+20
3L+2w+3L+2w=240
Sub the first equation in for L in the second equation and solve for w
3(w+20)+2w+3(w+20)+2w=240
3w+60+2w+3w+60+2w=240
10w+120=240
10w=240-120
10w=120
W=120/10
W=12
Sub w into the first equation and solve for L
L=w+20
L=12+20
L=32
Hope this helps!
3 0
4 years ago
If 1/2 gallon of paint covers 1/12 of a wall then how much paint is needed for the entire wall
netineya [11]

1/2 gallon of paint covers 1/12 of a wall , 12 times as much paint will cover 12 times the area you can solve this by 12*1/2=6.

5 0
3 years ago
-42 + 3x = 60 + 9x
muminat

Answer:

x = -17

Step-by-step explanation:

-42 + 3x = 60 + 9x

3x = 60 + 42 +9x

3x = 102 + 9x

-9x + 3x = 102

-6x = 102

x = -17

4 0
4 years ago
Jeremy subtracted the following rational expressions. His teacher told him that his answer was incorrect. Explain Jeremy's error
kkurt [141]
Since this is a subtraction problem, Jeremy needed to distribute the negative to the terms in the numerator. Jeremy only distributed it to the<span> x</span>2<span>-term, and not to 15. Instead, he kept the 15 positive. When he combined like terms, he got a result of 5 for the constants. The correct result is </span>x<span> + 5.</span>
9 0
3 years ago
Read 2 more answers
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