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grigory [225]
3 years ago
15

3x+ 2y= 4 solving for x

Mathematics
2 answers:
Jet001 [13]3 years ago
4 0

First step: Isolate the term that has x. To do that, subtract 2y from both sides.

3x + 2y = 4

3x = -2y + 4

Now divide both sides by 3.

x = \dfrac{-2y + 4}{3}

Pachacha [2.7K]3 years ago
4 0
First you subtract 2y and now you have 3x=-2y+4 then you decide my 3 and now your answer is x= -2/3+4/3 that’s your answer
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The height of dachshunds is usually 1/3 their length. If Mollie is 20 inches long, how tall is she?
arlik [135]

This is a proportion problem.

Let's make her Length x and her height 1/3 x.

1/3 x = 20 inches

x = 6 2/3 inches

Molly's height is 6 2/3 inches.

Check it.

6 2/3 x 3 = ? (change the mixed number to a fraction)

20/3 x 3 = ? (multiply)

60/3 = ? (divide)

20 inches. Yes, it checks.

8 0
3 years ago
Read 2 more answers
QUESTION IN THE ATTACHMENT
eimsori [14]

Answer:

A. The sum of the first 10th term is 100.

B. The sum of the nth term is n²

Step-by-step explanation:

Data obtained from the question include:

Sum of 20th term (S20) = 400

Sum of 40th term (S40) = 1600

Sum of 10th term (S10) =..?

Sum of nth term (Sn) =..?

Recall:

Sn = n/2[2a + (n – 1)d]

Sn is the sum of the nth term.

n is the number of term.

a is the first term.

d is the common difference

We'll begin by calculating the first term and the common difference. This is illustrated below:

Sn = n/2 [2a + (n – 1)d]

S20 = 20/2 [2a + (20 – 1)d]

S20= 10 [2a + 19d]

S20 = 20a + 190d

But:

S20 = 400

400 = 20a + 190d .......(1)

S40 = 40/2 [2a + (40 – 1)d]

S40 = 20 [2a + 39d]

S40 = 40a + 780d

But

S40 = 1600

1600 = 40a + 780d....... (2)

400 = 20a + 190d .......(1)

1600 = 40a + 780d....... (2)

Solve by elimination method

Multiply equation 1 by 40 and multiply equation 2 by 20 as shown below:

40 x equation 1:

40 x (400 = 20a + 190d)

16000 = 800a + 7600. ........ (3)

20 x equation 2:

20 x (1600 = 40a + 780d)

32000 = 800a + 15600d......... (4)

Subtract equation 3 from equation 4

Equation 4 – Equation 3

32000 = 800a + 15600d

– 16000 = 800a + 7600d

16000 = 8000d

Divide both side by 8000

d = 16000/8000

d = 2

Substituting the value of d into equation 1

400 = 20a + 190d

d = 2

400 = 20a + (190 x 2)

400 = 20a + 380

Collect like terms

400 – 380 = 20a

20 = 20a

Divide both side by 20

a = 20/20

a = 1

Therefore,

First term (a) = 1.

Common difference (d) = 2.

A. Determination of the sum of the 10th term.

First term (a) = 1.

Common difference (d) = 2

Number of term (n) = 10

Sum of 10th term (S10) =..?

Sn = n/2 [2a + (n – 1)d]

S10 = 10/2 [2x1 + (10 – 1)2]

S10 = 5 [2 + 9x2]

S10 = 5 [2 + 18]

S10 = 5 x 20

S10 = 100

Therefore, the sum of the first 10th term is 100.

B. Determination of the sum of the nth term.

First term (a) = 1.

Common difference (d) = 2

Sum of nth term (Sn) =..?

Sn = n/2 [2a + (n – 1)d]

Sn = n/2 [2x1 + (n – 1)2]

Sn = n/2 [2 + 2n – 2]

Sn = n/2 [2 – 2 + 2n ]

Sn = n/2 [ 2n ]

Sn = n²

Therefore, the sum of the nth term is n²

6 0
3 years ago
(Translate each sentence into a formula)
Brilliant_brown [7]

Answer:

A=πr2

THIS IS THE ANSWER

PLEASE MARK BRAINLIEST!!!!!

4 0
3 years ago
Will mark brainliest if you could explain this to me??
Rasek [7]

Your answer would be 4379 members because at the very beginning you had started off with 4372 members, however as the months go by changes happen. On october, it changed by -10, meaning that 10 students left the school meaning 4372-10=4362 members remaining. Then there's november with -8, so you subtract 8 from your new total 4362-8=4354. Then december comes, and this time it's a positive number, so you have to add 23 to 4354, giving you a new total of 4377. Then there's january, and its back to a negative number so you subtract 12 from 4377, 4377-12=4365. Then february comes and it's a change of a positive number, so you add 3 to the 4365, giving you 4368. And then finally by march, it's another positive number so you add 11 to your total, giving you 4379 students which are now at school. So basically if it's a negative change, subtract from the total, and if it is a positive, add to it. And you have to continue with the total that you got from the previous change that you did. Hope this was helpful

8 0
3 years ago
Read 2 more answers
If you know the 7x8=56 how can you use the Commutative Property of Multiplication to find the product of 8x7?
boyakko [2]

Answer:

The communicative property for multiplication states that the order of the multiplicands and can be swapped and the resulting product stays the same.

So

A * B = B * A

So if

7*8=56

then the commutative property says

8*7=56 as well since you can swap the order of the terms on the left and not change the result.

This property is true for addition and multiplication. It does not hold for subtraction or division.

Hope that makes sense and helps. (:

5 0
3 years ago
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