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2 years ago

What two number adds to 10 but multiply to 16

2 answers:

8 0

Let 2 nos. be x & y

x + y = 10

x * y = 16

from 1st eqn, y = 10 - x

substituting in 2nd eqn

x * (10 - x) = 16

10x - x^2 = 16

x^2 - 10x + 16 = 0

(x - 8)(x - 2) = 0

x = 8 or x =2

y = 10 - 8 = 2 or 10 - 2 = 8

so the two numbers are 2 and 8

yan [13]2 years ago

6 0

8 and 2 because 2+8=10 and 2 times 8 =16

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algol13

Answer:

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x = 13

Step-by-step explanation:

Since we are trying to distribute it evenly, we divide 104 by 8 to get 13 pieces of candy per child.

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Which of the following numbers could be the sides of a right triangle. A)8,15,17. B)6,8,12 C)9,11,21 D)4,13,16

ArbitrLikvidat [17]

Answer:

A) 8, 15, 17.

Step-by-step explanation:

Right triangle obey the Pythagorean theorem. Thus, we choose the two smaller numbers (being the cathetus) and if after applying the P. Theorem we get the biggest of each option (the hypotenuse) that means that those numbers could be the sides of a right triangle.

The Pythagorean theorem states that: $a^2+b^2=c^2$

Thus:

$\sqrt{a^2+b^2}=c$

Option A:

$\sqrt{8^2+15^2}=17$ → 17 = 17 OK!

Option B:

$\sqrt{6^2+8^2} = 10$ → 10 ≠ 12 NO

Option C:

$\sqrt{9^2+11^2} = [tex]\sqrt{202}$ [/tex] → $\sqrt{202}$ ≠ 21 NO

Option D:

$\sqrt{4^2+13^2} = \sqrt{185}$ → $\sqrt{185}$ ≠ 16 NO

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Step-by-step explanation:

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