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stiv31 [10]
3 years ago
11

Increase £84 by 23% TIA X

Mathematics
1 answer:
zmey [24]3 years ago
4 0

Answer:

103.32

Step-by-step explanation:

May way to answer a question like this

84(1+23/100)

Lets break it down:

Step 1.     23/100=0.23

Step2.     0.23+1=1.23

Step3.      1.23 x 84=103.32

I hope this helps You

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fiasKO [112]
B. x > -4 I did da test. That's da correct one :-)
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Find the value of x in the question
ICE Princess25 [194]

Answer:

x=52

Step-by-step explanation:

r=90 s=34  q=180-(90+34)

180-(90+34)=56

to find angle sqr

180-56=124

124=x+72

52=x

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Solve<br> -3x - y = 8<br> - 7x + 3y = -24
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The solution is (0,-8)
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Determine whether the set of all linear combinations of the following set of vector in R^3 is a line or a plane or all of R^3.a.
Temka [501]

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix  ⇒

\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right]

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right]

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&0\\0&1&2\\0&0&3\end{array}\right]

The set is linearly independent so the set of all linear combination of the set c. is all of R^3.

4 0
3 years ago
Simplify (−34.67) to the power of 0
fredd [130]

Answer:

-1

Step-by-step explanation:

anything to the power of zero is always going to be 1 or -1

5 0
3 years ago
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