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Montano1993 [528]
3 years ago
5

The ratio of girls to students at a middle school is 10 to 18. If there are 270 students at the school, how many are girls?

Mathematics
2 answers:
Ksju [112]3 years ago
5 0
10/18 = 0.5555 = 55.6%

0.556  <span>×  270 = 150
</span>
You are Correct! 



Stells [14]3 years ago
4 0
A good way of doing this problem would be to use cross multiplication of ratios
<u />\frac{10 girls}{18 students} = \frac{X girls}{270 students}

Then cross multiply

(10 girls)(270 students)=(X girls)(18 students)

2700=18x
150=x
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Fourteen subtracted from 2 times a number is 28. Write an equation?
Alecsey [184]

Step-by-step explanation:

let the unknown number be x

1St step: twice the number is 2(x) =2x

2nd step: 2x -14

3rd step: 2x - 14=28...

5 0
3 years ago
What is the value of x?
mel-nik [20]

Answer:

x = 24

Step-by-step explanation:

1.) put the equations together and equal them to 180

2x + 4 + 6x - 16 = 180

2.) combine like terms

8x - 12 = 180

3.) divide both sides by 8

8x = 192

4.) simplify

x = 24

7 0
3 years ago
-2(3y - 6) + 4(5y - 8) = 92
Whitepunk [10]

Answer:

y = 8

Step-by-step explanation:

-2(3y - 6) + 4(5y - 8) = 92\\\\\mathrm{Expand\:}-2\left(3y-6\right)+4\left(5y-8\right):\quad 14y-20\\14y-20=92\\\\\mathrm{Add\:}20\mathrm{\:to\:both\:sides}\\14y-20+20=92+20\\\\Simplify\\14y=112\\\\\mathrm{Divide\:both\:sides\:by\:}14\\\frac{14y}{14}=\frac{112}{14}\\\\Simplify\\y= 8

3 0
3 years ago
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What two pencils do i need to move to make three triangles?
asambeis [7]
Would this work? Hope it helps

6 0
3 years ago
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0
3 years ago
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