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3 years ago

What are the next two numbers? 0.03 0.12 0.21 ... ...

Mathematics

1 answer:

iris [78.8K]3 years ago

7 0

If it is 0.03,0.12,0.12 just add 0.09.
The next two numbers are 0.30,0.39

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Devaughn is 15 years younger than Sydney. The sum of their ages is 37 . What is Sydney's age?

posledela

Hi,
Let Sydney's age be x.
Devaughn=(x-15)
x+(x-15)=37
x+x-15=37
2x-15=37
2x=37+15
2x=52
x=52/2
x=26
Sydney is 26 years old.
Hope this Helps you.

7 0

3 years ago

4-(2x-3)=3 whats the answer

Oxana [17]

Hello there.

Explanation:

↓↓↓↓↓↓↓↓↓↓

$4-(2x-3)=3$

First, subtract by 4 from both sides.

$4-(2x-3)-4=3-4$

Second, simplify.

$-(2x-3)=-1$

Third, divide by -1 from both sides.

$\frac{-(2x-3)}{-1}=\frac{-1}{-1}$

Fourth, simplify.

$2x-3=1$

Next, add by 3 from both sides.

$2x-3+3=1+3$

Then simplify.

$2x=4$

Therefore, divide by 2 from both sides.

$\frac{2x}{2}=\frac{4}{2}$

Finally, simplify.

$x=2$

<u><em>Answer⇒⇒⇒⇒x=2</em></u>

Hope this helps!

Thank you for posting your question at here on Brainly.

-Charlie

8 0

2 years ago

The triathletes were offered water as they rode by the volunteer station. The volunteers handed them cones with the dimensions s

sladkih [1.3K]

Considering the volume of the cone, it is found that each triathlete sloshed out 9.5 cm³ of water.

<h3>What is the volume of a cone?</h3>

The volume of a cone of <u>radius r and height h</u> is given by:

V = 1/3 x r² x h

In this problem, the radius and the height are given as follows:

r = 3.5 cm, h = 7 cm.

Hence the total volume is:

V = 1/3 x 3.5² x 7 = 28.6 cm³

The triathletes sloshed out 1/3 of that, hence:

1/3 x 28.6 = 9.5 cm³.

More can be learned about the volume of a cone at brainly.com/question/14281550

#SPJ1

3 0

1 year ago

Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

4 0

11 months ago

I NEED HELP PLEASE IM BEGGING YOU PLEASE!!!!!!!!!!

olya-2409 [2.1K]

Answer:

why are you do such challing things in middle school

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers