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ozzi
3 years ago
13

If a variable has a distribution that is​ bell-shaped with mean 19 and standard deviation 7​, then according to the Empirical​ R

ule, 68.0​% of the data will lie between which​ values?
Mathematics
1 answer:
melamori03 [73]3 years ago
7 0
The empirical rule says that approximately 68% of a normal distribution falls within one standard deviation of the mean. In this case, this would include all values of the variable in the interval (19-7,19+7)=(12,26).
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Please help me!!!!!!!!!!!
Rzqust [24]
2. 1 1/2 each
3. 1 1/4 each
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3 years ago
PLEASE HELP ME!!!!!!! THIS IS TIMED!!!!!!!!! PLEASE HELP ME!!!!!!!!! PLEASE!!!!!!!!!!!!!
Cerrena [4.2K]

Answer:

the probability is 2/24 or 8.3%

Step-by-step explanation:

4 0
3 years ago
London was offered a job that paid a salary of \$93,000$93,000 in its first year. The salary was set to increase by 2% per year
Tema [17]

Answer: Amount = $143776

Step-by-step explanation:

Given that London was offered a job that paid a salary of $93,000 in its first year. The salary was set to increase by 2% per year every year.

Let P = 93000

Rate R = 2%

The amount of salary he will receive after 22 years can be calculated by using exponential equation

A = P(1 + 2%)^t

Where t = 22 years

A = 93000(1.02)^22

A = 93000 × 1.545979

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5 0
3 years ago
Read 2 more answers
Your company recently made a purchase of 25 identical tables. The purchase price after adding 5 percent sales tax was 1,706.25.
ELEN [110]
If c = the cost of one table, the cost of all 25 tables before sales tax is 25·c

Since the sales tax is 5%, or 0.05, the sales tax for 25 tables is 25·c·0.05

Adding the sales tax to the original cost of the 25 tables can give you:
25·c + 25·c·0.05 = 1706.25
1.05·25·c = 1706.25
26.25·c = 1706.25
c = \frac{1706.25}{26.25} = 65

so the refund for 5 tables would be 5*65 = $325
4 0
3 years ago
a fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 16 inches. Which measurement is closest to
gregori [183]

Answer:

The volume of the water in the fishbowl is equal to

(682\frac{2}{3})\pi\ in^{3}  or  2,144.6\ in^{3}

Step-by-step explanation:

we know that

The volume of the sphere (a fishbowl) is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

r=16/2=8\ in ----> the radius is half the diameter

substitute

V=\frac{4}{3}\pi (8^{3})=\frac{2,048}{3}\pi\ in^{3}

convert to mixed number

\frac{2,048}{3}\pi\ in^{3}=\pi (\frac{2,046}{3}+\frac{2}{3})=(682\frac{2}{3})\pi\ in^{3}

(3.14156)*(682\frac{2}{3})=2,144.6\ in^{3}

6 0
3 years ago
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