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tresset_1 [31]
3 years ago
6

60 + 2а – 4 = 2b + За

Mathematics
1 answer:
Brrunno [24]3 years ago
6 0

Answer:

56 - 2b = a

Step-by-step explanation:

Step 1:

60 + 2a - 4 = 2b + 3a

Step 2:

56 + 2a = 2b + 3a

Step 3:

56 = 2b + a

Answer:

56 - 2b = a

Hope This Helps :)

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Answer quickly please
KIM [24]

The correct answer is C.


You can tell this by factoring the equation to get the zeros. To start, pull out the greatest common factor.


f(x) = x^4 + x^3 - 2x^2


Since each term has at least x^2, we can factor it out.


f(x) = x^2(x^2 + x - 2)


Now we can factor the inside by looking for factors of the constant, which is 2, that add up to the coefficient of x. 2 and -1 both add up to 1 and multiply to -2. So, we place these two numbers in parenthesis with an x.


f(x) = x^2(x + 2)(x - 1)


Now we can also separate the x^2 into 2 x's.


f(x) = (x)(x)(x + 2)(x - 1)


To find the zeros, we need to set them all equal to 0


x = 0


x = 0


x + 2 = 0

x = -2


x - 1 = 0

x = 1


Since there are two 0's, we know the graph just touches there. Since there are 1 of the other two numbers, we know that it crosses there.

4 0
3 years ago
Read 2 more answers
What is a event made up of two or more simple events
kondaur [170]

Answer: A compound event is the combination of two or more simple events (with two or more outcomes).

Step-by-step explanation:

4 0
3 years ago
1. A weighted coin is biased so that a head is twice as likely to occur as a tail. If the coin is tossed 4 times, what is the pr
ohaa [14]

Answer:

80/81

Step-by-step explanation:

If a head is twice as likely to occur as a tail, then the probability of getting heads is 2/3 and the probability of getting tails is 1/3.

The probability of getting at least 1 head involves 4 scenarios:

1) 1 Head and 3 Tails

2) 2 Heads and 2 Tails

3) 3 Heads and 1 Tail

4) 4 Heads

Instead of calculate all these scenarios, you could calculate the opposite scenario: 4 Tails. The sum of all possible scenarios is 1, so:

P(at least one head) + P(no heads) = 1

Then, P(at least one head) = 1 - P(no heads)

The probability of 4 tails is:

P(no heads) = P(TTTT) = (1/3)(1/3)(1/3)(1/3)=1/81

Then, P(at least one head) = 1 - 1/81=80/81

7 0
3 years ago
What is the product of the two integer values for $x$ for which $|x^2 - 16|$ is a prime number?
Nana76 [90]

Answer:

-9

Step-by-step explanation:

x² -16 = (x -4)(x +4)

This magnitude of this product can only be prime if one of the factors is ±1. Any other integer value of x will produce a composite number (or zero).

... For x-4 = ±1, x = 3 or 5

... For x+4 = ±1, x = -3 or -5

The values of x that are ±3 both give |x²-16| = 7, a prime.

The values of x that are ±5 both give |x²-16| = 9, not a prime.

The two values of x that are of interest are x=-3 and x=3. Their product is ...

... (-3)·(3) = -9

8 0
3 years ago
What are the solutions to the equation (x-6)(x+8)=0?
Zepler [3.9K]

Answer:

x = 6, -8

Step-by-step explanation:

If (x - 6)(x + 8) = 0, that would imply that either (x - 6) or (x + 8) would equal zero. Using this, we can find that solving the two equations:

x - 6 = 0

and

x + 8 = 0

would yield the two solutions to the equation.

x - 6 = 0

Add 6 to both sides of the equation.

x = 6

So one of the solutions would be x = 6.

x + 8 = 0

Subtract 8 from both sides of the equation.

x = -8

So the other solution would be x = -8.

The two solutions are x = 6 and x = -8.

I hope you find my answer and explanation to be helpful. Happy studying.

6 0
3 years ago
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