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OLEGan [10]
3 years ago
7

Write a recursive formula for each sequence given or described below.

Mathematics
1 answer:
valentinak56 [21]3 years ago
7 0

Answer:

a_{n} =a_{n-1} +3000 and a₁ =30000 for n = 2,3,4,5,6, ......

Step-by-step explanation:

Doug has joined a job with a starting salary of $30000 per year.  

Hence, if a₁ is the salary of Doug in the first year, then  

a₁ =30000

Now, each year Doug will receive a raise of $3000 in his salary.

Hence, in the 2nd year, his salary(a₂) will become ( a₁ +3000) per year.

Again, in the 3rd year, his salary(a₃) will become ( a₂ +3000) per year.

Therefor, in the similar manner the recursive formula for his salary in each year will be given as a_{n} =a_{n-1} +3000 and a₁ =30000 for n = 2,3,4,5,6, ...... {aₙ is the yearly salary of Doug in the nth year} (Answer)

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C

Step-by-step explanation:

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How does -3-10= -13? Please explain
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The equation of liner is y = -x - 6. Line s includes the point (-1, -3) and is parallel to line
Reptile [31]

Answer:

90 hardcover books

Step-by-step explanation:

We can solve this by setting up a couple of equations.

Let's allow x to represent the number of paperbacks Tim owns, and allow y to represent the number of hardcover books he owns.

Using the information in the question, we can write the equations:

1)x = 4y-3

2) x+y=447

Let's rearrange equation 1 so that it is in standard form:

x-4y=-3

And then let's multiply equation 2 by 4 so that we can cancel out y when we solve the system of equations:

4(x+y=447)

4x+4y=1,788

Then we can add the two equations and solve for x:

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+ 2)4x+4y=1,788

------------------------------------

5x=1,785

x=357

So now we now the number of paperback books Tim has is 357. Let's plug this into one of the original equations to solve for the number of hardcover books (y):

357+y=447

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And now we know that Tim owns 90 hardcover books.

4 0
3 years ago
Our school's girls volleyball team has 14 players, including a set of 3 triplets: Alicia, Amanda, and Anna. In how many ways can
KatRina [158]

Answer:

990 ways to choose 6 starters out of 14 with exactly two of the three triplets.

Step-by-step explanation:

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= C(3,2) = 3! / (2!1!) = 3

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= C(11,4) = 11! / (4!7!) = 330

Total number of ways to choose 6 starters

= 3*330 = 990

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3 years ago
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