A.
B and C are wrong because x is more than or equal to 3.
D is wrong because y is the weight of oranges and cannot be negative.
Answer:
f(x) has moved:
4 units in the positive y direction i.e upwards
3 units in the positive x direction
Step-by-step explanation:
to get g(x), f(x) has undergone the following transformations
f(x) = x³
f1(x) = x³ + 4 (translation of 4 units in the positive y direction i.e upwards)
f2(x) = g(x) = (x-3)³ + 4 (translation of 3 units in the positive x direction i.e towards the right)
No, a cubic equation can not have three complex roots. This is because it turns twice and one end goes to positive infinity and one end goes to negative infinity. Thus, one of these MUST cross the x-axis at some point, meaning y = 0 and a real root exists.
Yes, a cubic equation can have three real roots if it cuts the x-axis three times.
Solution:
As, You have Written Polygon ABCD is a rectangle.
It is a Four sided Polygon , having all it's interior angles equal to 90°.As well as Opposite sides are equal(AB=CD,AD=BC), equal diagonals(AC=B D).
Join any of the diagonal of Rectangle either AC or B D.
In Right Δ ABC , Right angled at B
---(1)
In Right Δ ADC , Right angled at D
---(2)
Adding (1) and (2) that is LHS to LHS and RHS to RHS
Ar( Δ ABC) +Ar( Δ ADC)![=\frac{1}{2}\times[ AB \times BC+ AD \times DC]\\\\=\frac{1}{2}[2 \times AB \times BC][\text{As, AB=CD, and BC=AD}]\\\\ = AB \times BC](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%5B%20AB%20%5Ctimes%20BC%2B%20AD%20%5Ctimes%20DC%5D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%5B2%20%5Ctimes%20AB%20%5Ctimes%20BC%5D%5B%5Ctext%7BAs%2C%20AB%3DCD%2C%20and%20BC%3DAD%7D%5D%5C%5C%5C%5C%20%3D%20AB%20%5Ctimes%20BC)
So, Area of Rectangle= Product of any two Adjacent Sides