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dolphi86 [110]
3 years ago
9

Pattern is 3,-6,12,4,20

Mathematics
1 answer:
olchik [2.2K]3 years ago
5 0
Divide by 3 and add 16
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Heeelp<br> the first choices are linear or non linear<br> the second is increasing or decreasing
slega [8]
It’s non linear and it’s decreasing
5 0
3 years ago
In ΔSTU, m∠S = (10x-5)^{\circ}(10x−5)
Triss [41]

Answer:

Step-by-step explanation:

Ths sum of angle S,T,U is 180°. So,

10x-5 + 2x+4 + x-14 = 180

SOlve for x, and then you can find angle S.

4 0
3 years ago
Si la amplitud del complemento de un ángulo agudo es mayor, menor o igual que la del suplemento de un ángulo agudo. ¿podes respo
Harrizon [31]

Answer:

Dados dos ángulos vecinos, ambos son complementarios si la suma de sus medidas es igual a 90° y suplementarios si esa suma de medidas es igual a 180°. Puesto que uno de los ángulos es el ángulo agudo mencionado en el enunciado, es decir, un ángulo cuya medida es mayor que 0° y menor que 90°. Entonces, el ángulo complementario debe ser inevitablemente menor que el ángulo suplementario.

Step-by-step explanation:

Dados dos ángulos vecinos, ambos son complementarios si la suma de sus medidas es igual a 90° y suplementarios si esa suma de medidas es igual a 180°. Puesto que uno de los ángulos es el ángulo agudo mencionado en el enunciado, es decir, un ángulo cuya medida es mayor que 0° y menor que 90°. Entonces, el ángulo complementario debe ser inevitablemente menor que el ángulo suplementario.

5 0
3 years ago
Determine the equation of the linear function that generates the following table of values.
Mashutka [201]

Answer:

y = -19x + 14

Step-by-step explanation:

For each increase of x by 1, y decreases by 19, giving us -19x. When x = 0, y = 14, therefore, y = -19x + 14

5 0
2 years ago
What is the value of a over 6 plus 3 if a=48
AlexFokin [52]
Hello there!

By a over 6, I assume you mean a / 6? And by the wording, I assume 3 is outside of the fraction.

For the three outside the fraction,

(a / 6) + 3
(48 / 6) + 3
8 + 3
= 11

Hoped this help! If you have any more questions or need any more assistance, don't hesitate to friend me and message me! I can provide a mini lesson and a in-depth explanation as to what I did and why.
5 0
3 years ago
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