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uysha [10]
3 years ago
14

The aggregate annual rainfall at a given location is modeled as a random variable, resulting in a sequence of random variables {

V1, V2, V3, ...} for years 1, 2, 3,.... Assume the V's are independent, lognormally-distributed random variables with a mean value of 32in, and a coefficient of variation of 50%. It is desirable for the annual rainfall to be in the range between 15in and 50in. If this fails to be the case for multiple years, this can have adverse environmental and economic consequences.A) Find the probability a = P(15in < Vi \leq 50in).
B) For an arbitrary ten-year interval, nd the probability that the rainfall will not be in the desired range for at least three of the years in the interval.
Mathematics
1 answer:
EastWind [94]3 years ago
3 0

Answer:

hjbbbbgftjhtdfmyhmvbgmjvg

Step-by-step explanation:

hvvvvvvvvvvvvvvvvvv

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Something divided by something equals 132
natta225 [31]
11 x 12 =132
i think this is the right answer
8 0
3 years ago
Find the value of the integral that converges.<br> ∫^-5_-[infinity] x^-2 dx.
Bingel [31]

Answer:

\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}

Because the \lim_{x\to -\infty} \frac{1}{x} =0

The integral converges to \frac{1}{5}

Step-by-step explanation:

For this case we want to find the following integral:

\int_{-\infty}^{-5} x^{-2}dx

And we can solve the integral on this way:

\int_{-\infty}^{-5} x^{-2}dx= \frac{x^{-2+1}}{-2+1} \Big|_{-\infty}^{-5}

\int_{-\infty}^{-5} x^{-2}dx= -\frac{1}{x} \Big|_{-\infty}^{-5}

And if we evaluate the integral using the fundamental theorem of calculus we got:

\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}

Because the \lim_{x\to -\infty} \frac{1}{x} =0

The integral converges to \frac{1}{5}

8 0
3 years ago
Question 2 of 10
AnnyKZ [126]

The length of AB will be 10 units. Option B is corect. The formula for the distance between the two points is applied in a given problem.

<h3>What is the distance between the two points?</h3>

The length of the line segment connecting two places is the distance between them.

The distance between two places is always positive, and equal-length segments are referred to as congruent segments.

The given coordinate in the problem is;

(x₁,y₁)=(-2,-4)

(x₂, y₂)= (-8, 4)

The distance between the two points is found as;

\rm d= \sqrt{(-8-(-2))^2+(4-(-4))^2}\\\\ d=10 \ units

Hence, option B is corect.

To learn more about the distance between the two points, refer to;

brainly.com/question/16410393

#SPJ1

4 0
2 years ago
The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0
3 years ago
Ok so I need a date for prom I'm not trying to be wierd lol but ya,​
Pepsi [2]

Answer: Im down

Step-by-step explanation:

SAN DIEGO 619

8 0
3 years ago
Read 2 more answers
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