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uysha [10]
3 years ago
14

The aggregate annual rainfall at a given location is modeled as a random variable, resulting in a sequence of random variables {

V1, V2, V3, ...} for years 1, 2, 3,.... Assume the V's are independent, lognormally-distributed random variables with a mean value of 32in, and a coefficient of variation of 50%. It is desirable for the annual rainfall to be in the range between 15in and 50in. If this fails to be the case for multiple years, this can have adverse environmental and economic consequences.A) Find the probability a = P(15in < Vi \leq 50in).
B) For an arbitrary ten-year interval, nd the probability that the rainfall will not be in the desired range for at least three of the years in the interval.
Mathematics
1 answer:
EastWind [94]3 years ago
3 0

Answer:

hjbbbbgftjhtdfmyhmvbgmjvg

Step-by-step explanation:

hvvvvvvvvvvvvvvvvvv

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Determine algebraically whether f(x)=3x-2 and g(x)=(x+2)/3 are inverse functions. Show all work.
Sergio [31]

Answer:

Yes

Step-by-step explanation:

f(x)=3 x-2      

     

y= 3 x-2      

             

x= 3y - 2  

     

3 y -2 = x

3 y -2 + 2 = x + 2

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3        3       3

<u>3 y </u> =  <u>x  </u> +  <u>2  </u>                                                    

3        3       3

y =  <u>x </u>  +  <u>2   </u>        replace y with f ^ -1(x)

   <em> </em>  3        3                                            

f ^-1 (x) =    <u>x</u>   +  <u>2 </u>        

                 3       3      

4 0
3 years ago
Allen has a photo that is 6 in by 8 in. What will the dimensions of the photo be if he scales it down by a factor of one-half ?
Mice21 [21]
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6 0
3 years ago
What is the value of f(n+5)
Marat540 [252]

Using distributive property,

f * n = fn

f * 5 = 5f

= fn + 5f

7 0
3 years ago
Michelle had 600 fish to feed the dolphins in a zoo. Each dolphins ate the same number of fish. There are 9 dolphins in all. How
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4 0
3 years ago
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kirill [66]

Answer/Step-by-step explanation:

AC = 1.2

AB = 4

BC = 2.6

DF = 3

DE = 10

EF = 6.5

Thus:

\frac{DE}{AB} = \frac{10}{4} = \frac{5}{2}

\frac{DF}{AC} = \frac{3}{1.2} = \frac{3*10}{1.2*10} = \frac{30}{12} = \frac{5}{2}

\frac{EF}{BC} = \frac{6.5}{2.6} = \frac{6.5*10}{2.6*10} = \frac{65}{26} = \frac{5}{2}

The ratio of their corresponding sides are all equal to ⁵/2. Therefore, both triangles are similar.

4 0
3 years ago
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