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Elden [556K]
3 years ago
5

Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A

Mathematics
1 answer:
MAVERICK [17]3 years ago
4 0
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
    = -2cos4A*sin3A + 2cos4A*sinA
    = 2cos4A(sinA - sin3A)
    = 2cos4A*2cos(2A)sin(-A)
    = -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
   = 2cos4A*cos3A - 2cos4A*cosA
   = 2cos4A(cos3A - cosA)
   = 2cos4A*(-2)sin2A*sinA
   = -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
       = cos2A/sin2A
      = cot2A

This verifies the identity.
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Vera_Pavlovna [14]

Answer:

  • area: 16.28 ft²
  • perimeter: 17.05 ft

Step-by-step explanation:

The figure is shown as being composed of a semicircle and a triangle. You know the formula for the area of a circle is ...

  A = πr²

The radius of the semicircle is half its diameter, so is (4 ft)/2 = 2 ft. Then the area of a circle with radius 2 feet is ...

  A = π(2 ft)² = 4π ft²

Our semicircle has half that area, so ...

  area of semicircle = (4π ft²)/2 = 2π ft² ≈ 6.283 ft²

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The area of the triangle is given by the formula ...

  A = (1/2)bh

Here, the base is shown as 4 ft, and the height is shown as 5 ft. Then the triangle area is ...

  triangle area = (1/2)(4 ft)(5 ft) = 10 ft²

So, the total area of the composite figure is ...

  figure area = area of semicircle + triangle area

  = 6.283 ft² + 10 ft² ≈ 16.283 ft² . . . . area of the figure

__

The perimeter of the curved portion of the semicircle is half the circumference of a circle of radius 2 ft. It will be ...

  curved perimeter = (1/2)(2πr) = πr = π(2 ft) = 2π ft ≈ 6.283 ft

The length of each side of the triangle can be found from the Pythagorean theorem. Each side of the triangle is the hypotenuse of a right triangle with legs 2 ft and 5 ft. Then it will be ...

   triangle side length = √(2² +5²) ft = √29 ft ≈ 5.385 ft

The total perimeter is ...

   perimeter = 2 × triangle side length + semicircle length

  = 2×(5.385 ft) + 6.283 ft = 17.054 ft

The perimeter of the figure is about 17.05 feet.

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For sq root of 48

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