Question

What is the solution to the quadratic equation below? x^2-8x+16=11

Answer 1

Using it's formula, the solutions to the quadratic equation x² - 8x + 16 = 11 are: $x = -4 \pm \sqrt{11}$

What is a quadratic function?

A quadratic function is given according to the following rule:

$y = ax^2 + bx + c$

The solutions are:

$x_1 = \frac{-b + \sqrt{\Delta}}{2a}$

$x_2 = \frac{-b - \sqrt{\Delta}}{2a}$

In which:

$\Delta = b^2 - 4ac$

In this problem, the equation is:

x² - 8x + 16 = 11

In standard-form:

x² - 8x + 5 = 0

The coefficients are a = 1, b = -8, c = 5, hence:

$\Delta = (-8)^2 - 4(1)(5) = 44$

$x_1 = \frac{-8 + \sqrt{44}}{2} = -4 + \sqrt{11}$

$x_2 = \frac{-8 - \sqrt{44}}{2} = -4 - \sqrt{11}$

More can be learned about quadratic equations at brainly.com/question/24737967

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