Type I error says that we suppose that the null hypothesis exists rejected when in reality the null hypothesis was actually true.
Type II error says that we suppose that the null hypothesis exists taken when in fact the null hypothesis stood actually false.
<h3>
What is
Type I error and Type II error?</h3>
In statistics, a Type I error exists as a false positive conclusion, while a Type II error exists as a false negative conclusion.
Making a statistical conclusion still applies uncertainties, so the risks of creating these errors exist unavoidable in hypothesis testing.
The probability of creating a Type I error exists at the significance level, or alpha (α), while the probability of making a Type II error exists at beta (β). These risks can be minimized through careful planning in your analysis design.
Examples of Type I and Type II error
- Type I error (false positive): the testing effect says you have coronavirus, but you actually don’t.
- Type II error (false negative): the test outcome says you don’t have coronavirus, but you actually do.
To learn more about Type I and Type II error refer to:
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Answer:
the coefficient are 9 and -8
the constant is 6........
Answer:
The equation that describes the profit the store makes in a day that X units of yo-yo is sold is P= X × $8.00 - $50.00
Step-by-step explanation:
The information given are;
The price of each yo-yo = $8.00
The only available cost is the store clerk fee cost per day = $50.00
Let us call the number of yo-yo's sold per day as X
Therefore, the amount sold per day = X × $8.00
The company's profit, P = Total sales - Total cost
∴ P= X × $8.00 - $50.00
Therefore, the equation that describes the profit the store makes in a day that X units of yo-yo is sold = P= X × $8.00 - $50.00.
<span>The answer is in the thousands group. Its the way they word the problem that complicates it. 913,256 256 being the ones group 913 being the thousands group. So the name of the period with 913, is the thousands group</span>
Step-by-step explanation:
a) Perimeter is equal to 2w + 2L
2(3x + 4) + 2(x + 3)
6x + 8 + 2x + 6
8x + 14
b) Put 5 in x's place
8×5 + 14
40 + 14
54
c) Area = (3x + 4) * (x + 3)
Put 4 in x's place
(3×4 + 4) * (4 + 3)
12 + 4 * 7
16 * 7
112
