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anygoal [31]
3 years ago
7

Can someone help me with 19?

Mathematics
1 answer:
Lemur [1.5K]3 years ago
5 0
The volume of a pyramid is area of base times hight over 3. 
This should help you make an equation. 
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Factor out the coefficient of the variable 1/2q plus 5/2
Iteru [2.4K]
I believe you do it like this:
1/2 Q+5/2
divide 1/2 into each term
to divide multiply by the reciprocal
1/2 x2/1= 1
5/2 x 2/1=5

1/2(Q+5) 
8 0
3 years ago
The volume V (in cubic feet) of a right cylinder with a height of 3 feet and radius r (in feet) is given by V=3πr2. Solve the fo
Kitty [74]

Answer:

r=\sqrt{\frac{V}{3\pi}}\\\\r\approx 5.00\ ft

Step-by-step explanation:

-The volume of a cylinder is given by the formula:

V=3\pi r^2

#We make r the subject of the formula:

V=3\pi r^2\\\\r^2=\frac{V}{3\pi}\\\\r=\sqrt{\frac{V}{3\pi}}

#We then substitute for the stated volume and solve for r:

r=\sqrt{\frac{V}{3\pi}}, V=236\\\\\therefore r=r=\sqrt{\frac{236}{3\pi}}\\\\r=5.00404\approx\ 5.00\ ft

Hence, the cylinder's radius is approximately 5.00 ft

5 0
3 years ago
Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!
yan [13]

Answer:

\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}

Step-by-step explanation:

You need 2 things in order to solve this equation:  a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

cos(2\theta)=1-2sin^2(\theta)

so we will make that replacement, getting everything in terms of sin:

sin(\theta)+1=1-2sin^2(\theta)

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

2sin^2(\theta)+sin(\theta)=0

We can factor out the sin(theta), since it's common in both terms:

sin(\theta)(2sin(\theta)+1)=0

Because of the Zero Product Property, either

sin(\theta)=0 or

2sin(\theta)+1=0

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi.  They are:

\theta=\frac{\pi}{2},\frac{3\pi}{2}

The next equation needs to first be solved for sin(theta):

2sin(\theta)+1=0 so

2sin(\theta)=-1 and

sin(\theta)=-\frac{1}{2}

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval.  They are:

\theta=\frac{2\pi}{3},\frac{4\pi}{3}

7 0
3 years ago
What is 1 2/3 ÷ 1/8​
bekas [8.4K]
40/3 or 13.333333- your welcome
4 0
3 years ago
Read 2 more answers
What's 6/7 written as a fraction with a denominator of 42
uysha [10]
So we are trying to find the numerator of 42 in relation of 6/7.

42 divided by 7= 6    So 6 x 6 from the numerator of 6/7 = 36.

So 6/7 written as a fraction with a denominator of 42 is 36/42.
6 0
3 years ago
Read 2 more answers
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