Answer:
y=1/4x+6 1/4
Step-by-step explanation:
Answer:
P(A∩B) = 0.522
Step-by-step explanation:
Let's call A the event that a puppy is adopted and B the probability that a puppy live 7 or more years
So, the probability P(A∩B) that a randomly selected puppy in the shelter will get adopted and live 7 or more years is:
P(A∩B) = P(A)*P(B/A)
Because A and B are not independents.
Then, the probability P(A) that a puppy is adopted is 58% and the probability P(B/A) that a puppy live 7 or more years given that the puppy is adopted is 90%.
Finally, replacing the values, we get:
P(A∩B) = 0.58*0.9 = 0.522
It means that the 52.2% of the puppies are adopted and live 7 or more years.
The probability of not surviving a head-on car accident is: 0.903
Step-by-step explanation:
The probabilities of occurrence and non-occurrence of an event add up to one.
If p is the probability that an even will happen and q is the probability that it will not happen
Then

Here,
Probability of surviving = p = 0.097
Probability of not surviving = q = ?

The probability of not surviving a head-on car accident is: 0.903
Keywords: Probability, Inverse
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