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aliya0001 [1]
4 years ago
10

When 23Na is bombarded with protons, the products are 20Ne and A. a neutron B. an alpha particle C. a deuteron D. a gamma ray pa

rticle E. two beta particles
Physics
1 answer:
Vikki [24]4 years ago
5 0

Answer:

The correct option is B. an alpha particle.

Explanation:

When ²³Na is bombarded with protons _{1}^{1}\textrm{H}, ²⁰Ne and one alpha particle _{2}^{4}\textrm{He} is released.

The reaction is as follows:

_{11}^{23}\textrm{Na} + _{1}^{1}\textrm{H} \rightarrow _{10}^{20}\textrm{Ne} + _{2}^{4}\textrm{He}

Therefore, an alpha particle and ²⁰Ne are released when ²³Na is bombarded with protons.

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The question is incomplete. The complete question is :

Assume that the energy lost was entirely due to friction and that the total length of the PVC pipe is 1 meter. Use this length to compute the average force of friction (for this calculation, you may neglect uncertainties).

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Predicted range :  0.3503 m

Actual range : 1.09 m

Solution :

Given that :

The predicted range is 0.3503 m

Time of the fall is :

$t=\sqrt{\frac{2H}{g}}$

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(f)  = $7.307\times 10^{-3} \ v_0^2$

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i hope this helps

:)

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