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iVinArrow [24]
3 years ago
14

17. What is the speed of a race horse that runs 1500 m in 125 s?

Physics
2 answers:
Hoochie [10]3 years ago
6 0

Answer:

12 miles per second

Explanation:

likoan [24]3 years ago
3 0

Answer:

\boxed {\boxed {\sf 12 \ m/s}}

Explanation:

Speed is equal to distance divided by time.

s=\frac{d}{t}

The horse ran 1500 meters in 125 seconds.

d= 1500 \ m \\s= 125 \ s

Substitue the values into the formula.

s= \frac{ 1500 \ m }{125 \ s}

Divide.

s= 12 \ m/s

The speed of the race horse is 12 meters per second.

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Pie

Answer:

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6 0
2 years ago
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2. A rock is dropped off a bridge. How fast is the rock
zhenek [66]

Answer:

a) The velocity of rock at 1 second, v = 9.8 m/s

b) The velocity of rock at 3 second,  v = 29.4 m/s

c) The velocity of rock at 5.5 second,  v = 53.9 m/s

Explanation:

Given data,

The rock is dropped from a bridge.

The initial velocity of the rock, u = 0

a) The velocity of rock at 1 second,

   Using the first equation of motion

                         v = u + gt

                         v = 0 + 9.8 x 1

                          v = 9.8 m/s

b) The velocity of rock at 3 second,

                         v = u + gt

                         v = 0 + 9.8 x 3

                          v = 29.4 m/s

c) The velocity of rock at 5.5 second,

                         v = u + gt

                         v = 0 + 9.8 x 5.5

                         v = 53.9 m/s

5 0
3 years ago
Calculate the total energy of 2.0 kg object moving horizontally at 10 m/s 50 meters above the surface
mina [271]
We have:

Total Energy: KE + GPE
KE (Kinetic Energy) = \frac{1}{2} m*v^2
GPE (Gravitational Potential Energy) = m*g*h

Data:
m (mass) = 2.0 Kg
v (speed) = 10 m/s
h (height) = 50 m
Use: g (gravity) = 10 m/s²

Formula:

Total Energy: KE + GPE
TE =  \frac{1}{2} m*v^2 + m*g*h

Solving:
TE = \frac{1}{2} m*v^2 + m*g*h
TE = \frac{1}{2} *2.0*10^2 + 2.0*10*50
TE =  \frac{2.0*100}{2} + 1000
TE =  \frac{200}{2} + 1000
TE = 100 + 1000
\boxed{\boxed{TE = 1100\:Joule}}\end{array}}\qquad\quad\checkmark


5 0
3 years ago
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What was the name of charles lindbergh’s single winged airplane for his solo flight across the atlantic?
aev [14]

Answer:

Spirit of St. Louis

Explanation:

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The plane he used was the Spirit of St. Louis which took more than 33 hours to complete the journey. It was the first successful flight of this kind. The airplane flew from Long Island on May 20 and landed in Paris on May 21.

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Explanation:

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