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3 years ago

17. What is the speed of a race horse that runs 1500 m in 125 s?

Physics

2 answers:

Hoochie [10]3 years ago

6 0

Answer:

12 miles per second

Explanation:

likoan [24]3 years ago

3 0

Answer:

$\boxed {\boxed {\sf 12 \ m/s}}$

Explanation:

Speed is equal to distance divided by time.

$s=\frac{d}{t}$

The horse ran 1500 meters in 125 seconds.

$d= 1500 \ m \\s= 125 \ s$

Substitue the values into the formula.

$s= \frac{ 1500 \ m }{125 \ s}$

Divide.

$s= 12 \ m/s$

The speed of the race horse is 12 meters per second.

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3 years ago

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The area of the tympanic membrane is 100 mm 2 and the area of the oval window is 5 mm 2 . if a sound wave applies 10 n to the ty

Flura [38]

The answer is "0.5N".

According to the question;
P1=P2
so,
F1/A1= F2/A2

P=(F/A)

A1=100mm²

F1= 10N

A2= 5mm²

F2= ?

F2= ((F1 x A2)/A1)
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=0.5N

8 0

3 years ago

A typical garden hose has an inner diameter of 5/8". Let's say you connect it to a faucet and the water comes out of the hose wi

castortr0y [4]

Since speed (v) is in ft/sec, let's convert our diameters from inches to feet:
1) 5/8in = 0.625in
0.625in × 1ft/12in = 0.0521ft
2) 0.25in × 1ft/12in = 0.021ft
Equation:
$v = 4q \div ( {d}^{2} \pi) \: where \: q = flow \\ v = velocity \: (speed) \: and \: \\ d = diameter \: of \: pipe \: or \: hose \\ and \: \pi = 3.142$
$we \: can \: only \: assume \:that \\ flow \: (q) \:stays \: same \: since \: it \\ isnt \: impeded \: by \: anything \\ thus \:it \: (q)\: stays \: the \: same \: \\ so \: 4q \: can \: be \: removed \: from \: \\ the \: equation$
$then \: we \: can \: assume \: that \: only \\ v \: and \: d \: change \: leading \:us \: to > > \\ (v1 \times {d1}^{2} \pi) = (v2 \times {d2}^{2}\pi)$
$both \: \pi \: will \: cancel \: each \: other \: out \: \\ as \: constants \:since \: one \: is \: on \\ each \: side \: of \: the \: =$

$(v1 \times {d1}^{2}) = (v2 \ \times {d2}^{2}) \\ (7.0 \times {0.052}^{2}) = (v2 \times {0.021}^{2}) \\ divide \: both \: sides \: by \: {0.021}^{2} \\ to \: solve \: for \: v2 > >$
$v2 = (7.0)( {0.052}^{2} ) \div ( {0.021}^{2}) \\ v2 = (7.0)(.0027) \div (.00043) \\ v2 = 44 \: feet \: per \: second$
new velocity coming out of the hose then is
44 ft/sec

4 0

3 years ago

Express force in terms of base units

denis-greek [22]

Answer:

F = [MLT⁻²]

Explanation:

Force = ma

m (mass) = [M]

a (acceleration) = [LT⁻²]

F(force) = m x a = [MLT⁻²]

3 0

3 years ago

A 5.0 kg wooden block is placed at an adjustable inclined plane. what is the angle of incline above which the block will start t

Aleks [24]

The value of the angle of the incline $\theta$ at which the block starts to slide is the angle at which the component of the weight parallel to the incline becomes equal to the frictional force that keeps the block on the incline:
$mg \sin \theta = \mu N$
where the term on the left is the component of the weight parallel to the incline, and the term on the right is the frictional force, which is the product between the coefficient of friction $\mu$ and the normal reaction of the incline N.

The normal reaction of the incline, N, is equal to the component of the weight perpendicular to the incline:
$N=mg \cos \theta$
Therefore, the initial equation becomes
$mg \sin \theta = \mu mg \cos \theta$
From which we find
$\tan \theta = \mu$
$\theta = \arctan \mu$

For angles above this value, the block will start sliding down, otherwise the block will stay on the incline.

3 0

3 years ago