How to do this please
1 answer:
Answer:
1) see the diagram below
2) (b) the length of the wire being tested
Explanation:
1) An <em>ammeter</em> is connected in series with the circuit branch in which you want to measure current. "Conventional current" enters the positive terminal of the ammeter. (You can think of it as a voltmeter across a small resistor. The polarity of the voltage matches the polarity of the current.)
A <em>voltmeter</em> is connected in parallel with the circuit element of interest. Here, you want to measure the voltage across the wire, so the voltmeter is placed in parallel with the wire. The positive terminal of the voltmeter is connected to the end of the circuit element that has the higher (more positive) potential.
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2) The wording of the problem tells you which variable is independent:
"A <em>varies with</em> B" means the independent variable is B
Here, the independent variable is the length of the wire.
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Answer:
Induced emf in the loop is 0.02208 volt.
Induced current in the loop is 0.0368 A.
Explanation:
Given that,
Area of the single loop,
The initial value of uniform magnetic field, B = 3.8 T
The magnetic field is decreasing at a constant rate,
(a) The induced emf in the loop is given by the rate of change of magnetic flux.
(b) Resistance of the loop is 0.6 ohms. Let I is the current induced in the loop. Using Ohm's law :
Hence, this is the required solution.