The light collected by a telescope is proportional to the area of the telescope.
The area of a telescope is π * (Diameter / 2) ^2 = π * (Diameter)^2 / 4.
So, for the 20.0 cm telescope, area = π * (20.0cm)^2 / 4.
And for the 5.0 cm telescope, area = π * (5.0 cm)^2 / 4
So, divide both expressions to find the ratio of collection of light of one telescope to the other:=> (20.0)^2 / (5.0)^2 = (20.0 / 5.0)^2 = 4^2 = 16
Then, the 20.0 cm telescope collects 16 times the ligth that the 5.0 cm telescope collect. <--- answer
Answer:
Option 1 is endothermic
Option 2 is exothermic
Explanation:
In Chemistry, Exothermic reactions are reactions whereby heat energy is transferred to the surroundings and the temperature of the surroundings increases. Endothermic reactions are those whereby heat energy from the surroundings is absorbed and thereby making the temperature of the surroundings to decrease.
This means in simple terms that endothermic reactions will have heat on the reaction side of the equation while exothermic will have heat on the product side of the equation.
Thus;
Option 1 is endothermic since it has heat absorbed on the reactant side.
Option 2 is exothermic since it gives off heat on the product side.
Answer:
a.They have a smaller proportion of heavy elements.
Explanation:
As a star grows old , its metal content becomes low . Our sun is Population I star which means it is very new . Its metal content is 1.4 % . By the term metal we mean any element heavier than helium . Population II stars are older than population I stars . They will have lesser content of metal . Population III are oldest star group which have metal content as less as .015 % .
Answer:
The magnitude of the uniform magnetic field exerting this torque on the loop is 1.67 T
Explanation:
Given;
radius of the wire, r = 0.45 m
current on the loop, I = 2.4 A
angle of inclination, θ = 36⁰
torque on the coil, τ = 1.5 N.m
The torque on the coil is given by;
τ = NIBAsinθ
where;
B is the magnetic field
Area of the loop is given by;
A = πr² = π(0.45)² = 0.636 m
τ = NIBAsinθ
1.5 = (1 x 2.4 x 0.636 x sin36)B
1.5 = 0.8972B
B = 1.5 / 0.8972
B = 1.67 T
Therefore, the magnitude of the uniform magnetic field exerting this torque on the loop is 1.67 T
Answer:
Sound waves travel at 343 m/s through the air and faster through liquids and solids. The waves transfer energy from the source of the sound, e.g. a drum, to its surroundings. Your ear detects sound waves when vibrating air particles cause your ear drum to vibrate. The bigger the vibrations the louder the sound.
Explanation:
