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AleksandrR [38]

4 years ago

11

The speed of sound is approximately 340 m / s. How long will it take for the sound to travel from the batter to a spectator who

is seated 30 meters away? How long will it take if the spectator is 150 meters away?

1 answer:

iris [78.8K]4 years ago

4 0

The first answer is 3/34 sec and the second answer is 15/34 sec.

Set up a proportion for these problems. For the first question,
340/1 = 30/x

Cross multiply:
340*x = 1*30
340x = 30

Divide both sides by 340:
340x/340=30/340
x = 30/340 = 3/34

For the second question,
340/1 = 150/x

Cross multiply:
340*x = 150*1
340x=150

Divide both sides by 340:
340x/340 = 150/340
x = 150/340 = 15/34

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3 years ago

A triangle has vertices at (-9,2), (-9,-6), (-3,-6). What is the perimiter of the triangle in units?

vladimir2022 [97]

Answer:

The perimeter is 24 units

Step-by-step explanation:

Given

$A = (-9,2)$ --- $(x_1,y_1)$

$B = (-9,-6)$ --- $(x_2,y_2)$

$C = (-3,-6)$ --- $(x_3,y_3)$

Required

Determine the perimeter

To do this, we calculate the distance AB, BC and AC.

Distance is calculated as:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

So, we have:

$AB = \sqrt{(-9 - -9)^2 + (2 - -6)^2$

$AB = \sqrt{64$

$AB = 8$

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$BC = 6$

$AC = \sqrt{(-9 --3)^2 + (2 --6)^2$

$AC = \sqrt{100$

$AC = 10$

So, the perimeter (P) is:

$P = AB + BC + AC$

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3 years ago

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Answer:

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hope it helps :)

Step-by-step explanation:

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3 years ago

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Feliz [49]

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now, the sprinkler does 1/15 of the lawn in 1/3 of an hour, how long will it be to do the whole 15/15?

$\bf \begin{array}{ccll}
lawn&hours\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{15}&\frac{1}{3}\\\\
\frac{15}{15}&h
\end{array}\implies \cfrac{\quad \frac{1}{15}\quad }{\frac{15}{15}}=\cfrac{\quad \frac{1}{3}\quad }{h}\implies \cfrac{1}{15}\cdot \cfrac{15}{15}=\cfrac{\quad \frac{1}{3}\quad }{\frac{h}{1}}
\\\\\\
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6 0

3 years ago

Read 2 more answers