2.50 / 8 = 0.3125.
8 * 3 = 24
<span>0.3125 * 4 = 1.25</span>
2.50 * 3 = 7.5 + 1.25
= 8.5
8.5 should be final answer.
5km = 5000 meters
450m+800m= 1250m
5000m-1250m= 3,750m
3 3/4 km
Slope-intercept form:
y = mx + b
"m" is the slope, "b" is the y-intercept (the y value when x = 0 or (0,y))
You know m = -3, so you can plug it into the equation
y = mx + b
y = -3x + b
To find "b", plug in the point (4,-2) into the equation
y = -3x + b
-2 = -3(4) + b
-2 = -12 + b Add 12 on both sides
10 = b
y = -3x + 10 Your answer is B
A and F are the only set of ordered pairs that work in both of the equations above. In order to find these you must place them into each equation and check for truth. Below is the work for A and F.
Ordered Pair A : (0,6)
y > 6x + 5
6 > 0 + 5
6 > 5 (TRUE)
y < -6x + 7
6 < 0 + 7
6 < 7 (TRUE)
Ordered Pair F : (-2, 18)
y > 6x + 5
18 > - 12 + 5
18 > -7 (TRUE)
y < -6x + 7
18 < 12 + 7
18 < 19 (TRUE)
Answer:
a. i. x ≤ 25 ii. 16 < x < 35 iii. 25 < x ≤ 95
b. The second and third car seats are appropriate for a 35 lb child.
Step-by-step explanation:
a. Model those ranges with compound inequalities
Let x represent the car seat.
i. A car seat designed for a child weighing up to and including 25 lb is described by the inequality.
x ≤ 25
ii. A car seat designed for a child weighing between 16 lb and 35 lb is described by the inequality.
16 < x < 35
iii. A car seat designed for a child weighing between 25 lb and 95 lb inclusive is described by the inequality.
25 < x ≤ 95
b. Which car seats are appropriate for a 33-lb child?
Since 35 lb is included in the range of the inequalities for the second and third card seats, the second and third car seats are appropriate for a 35 lb child.