Answer:
The speed rate of the plane in still air is 1006.67 km/h
The speed rate of the wind is 246.67 km/h
Step-by-step explanation:
To answer the question, we let the speed of the plane in still air = x km/h
Let the speed of the wind = y km/h
Therefore,
4560/(x - y) = 6 hours and
3720/(x + y) = 3 hours
4560 = 6·x - 6·y.........(1)
3720 = 3·x + 3·y ........(2)
Multiplying equation (2) by 2 and add to (1) gives
12080 = 12·x
x = 12080/12 =
km/h
Substituting the value of x in (1) gives
4560 = 6040 - 6·y
6·y = 1480
y = 1480/6 = 
The speed rate of the plane in still air = 1006.67 km/h
The speed rate of the wind = 246.67 km/h.
Measure the resting heart rate and then after the 100 meters check it agian.
If this helps mark brainliest if not use your brain.
You need to include the actual picture of the graph :)
Answer:
ΔHFG≅ΔSUT
Step-by-step explanation:
You just have to match up the sides and the angle.It's easier to color code them.
For example:
Segment SU would be congruent with HF. (both would be blue, just example color)
Angle U is congruent to angle F (red)
UT congruent to FG (green)