24 because 8 times 3 is 24 and 6 times 4 is 24. It is the smallest number both can be multiplied by a number to get 24.
1. 10 + 6(-9-4x)=10(x-12)+8
2.10 +-45-24x=10x-120+8
3.10 +7 = 34x -120 +8
4.17=34x-120+8
5.17=34x +128
6. 34x=115
7.x= 0.29565217391
Set them equal to each other and solve
3x + 39 = 4x +34
-x=-5
X=5
Plug it in
3(5) + 39 = 54
4(5) +34 = 54
For the final angle ,
54 + 54 = 108
180-108 =72
The angle measures are 54,54, and 72
9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
The first term, a, is 2. The common ratio, r, is 4. Thus,
a_(n+1) = 2(4)^(n).
Check: What's the first term? Let n=1. Then we get 2(4)^1, or 8. Is that correct? No.
Try this instead:
a_(n) = a_0*4^(n-1). Is this correct? Seeking the first term (n=1), does this formula produce 2? 2*4^0 = 2*1 = 2. YES.
The desired explicit formula is a_(n) = a_0*4^(n-1), where n begins at 1.