Answer:
If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 15 minutes
Sample size, n = 10
Alpha, α = 0.05
Population standard deviation, σ = 4 minutes
First, we design the null and the alternate hypothesis
Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.
Formula:
Now,
Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.
Thus, we can write:

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.
Pq + pr = 80 => p (q+r) = 80
pq + qr = 425 => q (p+r ) = 425
Factorize 80 with having one factor as prime number
80 = 2 * 40 = 5 *16
Factrorize 425 with having one factor as prime number
425 = 5 * 85 = 17 * 25...
Therfore, p has to be 2.
q = 17 and r= 23...
p + q +r = 2 + 17+ 23 = 42
Answer:
THE ANSWER IS C
Step-by-step explanation:
X + (x + 1) + (x + 2) + (x + 3)
4x + 6