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noname [10]
3 years ago
14

How is the graph of y=(x-1)2-3 transformed to produce the graph of y-3(x+4)??

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
4 0

Step-by-step explanation:

How is the graph of y=(x-1)2-3 transformed to produce the graph of y-3(x+4)??

The graph is translated left 5 units, compressed vertically by a factor of 2, and translated up 3 units.

The graph is stretched vertically by a factor of Ź, translated left 5 units, and translated up 3 units.

O The graph is translated left 5 units, compressed horizontally by a factor of 3, and translated down 3 units.

O The graph is stretched horizontally by a factor of Ž, translated left 5 units, and translated down 3 units.

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Please Help Me! I need to pass.
Andru [333]
42 is the answer

Explanation:
50% of 80 is half of 80 which is 40

Then you would add 40 with 5% of 40

What you would do then is 5% times 40 then you would change the 5% into a decimal which is 0.05 and multiply it by 40 , which would get u 2

Then you would add the price with tax
40+2 = 42
6 0
2 years ago
How do you convert set notation to interval notation?
Semenov [28]

Answer:

Imagine we are to express  [ a , b ]  in set notation

A = [ a , b ] , then  A = { x  ∈  R  /  a ≤ x ≤ b }

In this notation we define the characteristics of all  x  belonging to this set  A ....x must be greater or equal to a and simultaneously smaller or equal to b...

Interval notation is other way to say the same but assuming that  means the extreme a is IN the interval and  means extreme  a  is not.

6 0
3 years ago
Three angles of a quadrilateral are 75°, 90° and 75°. What is the measure of the fourth angle?
Sergio039 [100]

the inside of quadrilateral is always 360°.So add 75°,90° and 75° and then subyaract from360°.

x+75°+75°+90°=360

×+240°=360°

x=360°-240°

x=120°

4 0
3 years ago
Please answer the following questions​
laila [671]

Answer:

4a) 110 square centimetres

4b) 127 square centimetres

6) 292 square centimetres

8) 800 tiles

Step-by-step explanation:

4. We need to find the area of the large rectangle and then deduct the area of the unshaded part:

a) The large rectangle has dimensions 12 cm by 15 cm. Its area is:

A = 12 * 15 = 180 square centimetres

The unshaded part has a length of 15 - (3 + 2) cm i.e. 10 cm and a width of 7 cm. Its area is:

a = 10 * 7 = 70 square centimetres

Therefore, the area of the shaded part is:

A - a = 180  - 70 = 110 square centimetres

b) The large rectangle has dimensions 13 cm by 11 cm. Its area is:

A = 13 * 11 = 143 square centimetres

The unshaded part has dimensions 8 cm by 2 cm. Its area is:

a = 8 * 2 = 16 square centimetres

Therefore, the area of the shaded part is:

A - a = 143 - 16 = 127 square centimetres

6. The background area of the space not covered by the photograph is the area of the frame minus the area of the photograph.

The frame has dimensions 24 cm by 18 cm. Therefore, its area is:

A = 24 * 18 = 432 square centimetres

The photograph has dimensions 14 cm by 10 cm. Therefore, its area is:

a = 14 * 10 = 140 square centimetres

Therefore, the background area of the space not covered by the photograph is:

A - a = 432 - 140 = 292 square centimetres

8) The floor has dimensions 8 m by 4 m. The area of the floor is:

A = 8 * 4 = 32 square centimetres

Each square tile has dimensions 20 cm by 20 cm. In metres, that is 0.2 m by 0.2 m. The area of each tile is:

a = 0.2 * 0.2 = 0.04 square metres

The number of tiles that are needed is the area of the floor divided by the area of each tile:

A / a = 32 / 0.04 = 800 tiles

4 0
3 years ago
indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and
vladimir1956 [14]

The equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5) is <u>12x - 2y = 13</u>.

In the question, we are asked to indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5).

The slope of the line with endpoints (-1,6) and (5,5), can be calculated as:

m = (6 - 5)/(-1 - 5) = 1/(-6) = -1/6.

Thus, the slope of the perpendicular bisector = -1/m = -1/(-1/6) = 6.

The perpendicular bisector passes through the midpoint of the line with endpoints (-1,6) and (5,5), which can be calculated as:

(x₁, y₁) = ( {(-1 + 5)/2},{(6 + 5)/2} ),

or, (x₁,y₁) = (2, 11/2).

Thus, the required equation can be shown as:

(y - 11/2) = 6(x - 2), which can be shown in the standard form as follows:

(2y - 11)/2 = 6x - 12,

or, 2y - 11 = 12x - 24,

or, 12x - 2y = 13.

Thus, the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5) is <u>12x - 2y = 13</u>.

Learn more about the equation of perpendicular bisector at

brainly.com/question/20608689

#SPJ4

4 0
1 year ago
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